It is instructed to subtract (2a−3b+4c) from the sum of (a+3b−4c),(4a−b+9c) and (−2b+3c−a).
So, First we will do the sum of the three given polynomials,
Sum =(a+3b−4c)+(4a−b+9c)+(−2b+3c−a)
=(a+4a−a)+(3b−b−2b)+(−4c+9c+3c)
=4a+8c
Now, we can perform the subtraction,
∴ Required difference
=(4a+8c)−(2a−3b+4c)
=4a+8c−2a+3b−4c
=2a+3b+4c
Answer:380
Step-by-step explanation:
500-120=380
Answer:
Price is $ 30
Step-by-step explanation:
Regular price = $75
Discount = 60%
First we find the 60% of 75
( 75 × 60 ) ÷ 100 = 45
Now this answer with regular price
75 - 45 = 30
MARK BRAINLIEST IF YOU UNDERSTAND
<em>For another information, when D > 0, there are 2 real roots.</em>
<em>When D = 0, there is only one real root.</em>
<em>And when D < 0, there are no real roots (also known as imaginary.)</em>
Answer:
please in English I don't understand spanish
Step-by-step explanation:
