Question

Solve the quadratic equation by using the quadratic formula. 2x^2-5x+1=0

Answer 1

Answer:

$x = \frac{5 + \sqrt{17} }{4}$

Answer 2

Answer:

Answer: x is 2.28 and 0.22

Step-by-step explanation:

• From the quadratic formular of general equation ax² + bx + c = 0

$x = \frac{ - b± \sqrt{ {b}^{2} - 4ac } }{2a}$

• By comparison with equation given:

a » 2, b » -5, and c » 1

• substitute:

$x = \frac{ - ( - 5)± \sqrt{ {( - 5)}^{2} - (4 \times 2 \times 1) } }{(2 \times 2)} \\ \\ x = \frac{5± \sqrt{17} }{4} \\ \\ x = 2.28 \: \: and \: \: 0.22$