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Reptile [31]
3 years ago
13

Please can you help me

Mathematics
1 answer:
Lapatulllka [165]3 years ago
6 0

Answer:

x  ≤  5

Step-by-step explanation:

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The answer is -10/3 your answer
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How do I solve this?​
Paladinen [302]

Answer:

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Step-by-step explanation:

i added and subtracted and got 4

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Temp of 20* C will drop by 4*c
svp [43]

Answer:

16* C

Step-by-step explanation:

This is simply 20 - 4

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Thus, 16° C

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3 years ago
Find the roots of:
Elena-2011 [213]

\large\displaystyle\text{$\begin{gathered}\sf \pmb{1) \  2x^3-7x^2+8x-3=0 } \end{gathered}$}

Synthetic division is used since the equation is of the third degree. The divisors of -3 are 1, -1, 3, +3. So:

  | 2  -7    8  -3

<u>1 |      2   -5   3</u>

  | 2   -5    3  0

<u> 1 |      2     -3   </u>

    2   -3     0

So the factorization is (x-1)² (2x-3)=0. So:

                     \bf{ x_1=x_2=1 \qquad x_2=\dfrac{3}{2}  }

\large\displaystyle\text{$\begin{gathered}\sf \pmb{2) \  x^3-x^2-4=0 } \end{gathered}$}

Synthetic division is used since the equation is of the third degree. The divisors of -4 are 1, -1, 2, -2, 4, -4. So:

      |  1  -1  0  -4

  <u>2  |     2  2     </u>

         1  2  2  0

So the factorization is (x-2)(x²+x+2)=0 . When calculating the discriminant of the trinomial, it is concluded that it has no roots since the result is negative. So you only have one solution.

                   \bf{ 1^2-4(2)(2)=1-16=-15 < 0 \quad \Longrightarrow \quad x=2 }

\large\displaystyle\text{$\begin{gathered}\sf \pmb{3) \  6x^3+7x^2-9x+2=0 } \end{gathered}$}

Synthetic division is used since the equation is of the third degree. The divisors of 2 are 1, -1, 2, -2. So:

   | 6    7       9      2

<u>-2 |      -12    10     -2</u>

     6    -5     1       0

So the factorization is (x+2)(6x²-5x+1)=0 . The quadratic equation is solved by the general formula:

         \bf{ x_{2, 3}&=\dfrac{5\pm \sqrt{(5)^2-4(6)(1)}}{2(6)}=\dfrac{5\pm \sqrt{25-24}}{12}=\dfrac{5\pm 1}{12} }}

                     \large\displaystyle\text{$\begin{gathered}\sf  \begin{matrix} x_1=-2&\ \ \ \ \ \ x_{2}=\dfrac{6}{12} \qquad &\ \ \ x_3=\dfrac{4}{12}\\ &\ \ \ x_2=\dfrac{1}{2} \qquad &x_3=\dfrac{1}{3} \end{matrix} \end{gathered}$}

6 0
2 years ago
Val rented a bicycle while she was on vacation. She paid a flat rental fee of f dollars, plus $8.50 each day. The total cost at
damaskus [11]

The question is incomplete. Here is the complete question:

Val rented a bicycle while she was on vacation. She paid a flat rental fee of f dollars, plus $8.50 each day. The total cost at the end of her vacation was t dollars. Let d represent the number of days Val rented the bicycle. Write an equation representing the total cost at the end of her vacation.

Answer:

t=f+8.5d

Step-by-step explanation:

Given:

Flat rental fee = f

Variable fee per day = $8.50

Total cost at the end vacation = t

Number of days of her vacation = d

Using unitary method, we can find the variable fee for 'd' days.

1 day variable fee = $8.50

Therefore, 'd' days variable fee = 8.50d

Total cost at the end of her vacation can be obtained by adding the fixed rental fee and the variable fee obtained for the given number of days.

Now, total cost is given as:

Total cost = Flat rental fee + Variable fee

Substituting all the variables and framing above in the form of an equation, we get:

t=f+8.5d

Therefore, the equation representing the total cost at the end of her vacation is t=f+8.5d

7 0
3 years ago
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