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Reptile [31]
3 years ago
13

Please can you help me

Mathematics
1 answer:
Lapatulllka [165]3 years ago
6 0

Answer:

x  ≤  5

Step-by-step explanation:

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Answers and step by step explanations please?(Just one example)​
Allushta [10]
Answer is 4x x 3y >e3£
5 0
3 years ago
What is another way to write 49*12? 1. 50*10<br> 2. 50*10+2<br> 3. 50*12-12 <br> 4. 50+12-12
Umnica [9.8K]
49×12= 588
1. 50×10=500
2. 50×10+2= 502 
3. 50×12-12= 588
4. 50+12-12=50

Another way to write 49×12 is 50×12-12

4 0
3 years ago
Yeah i need help anyone?
Anika [276]

Answer:

A

Step-by-step explanation:

A secant is a line that goes through a circle at two points.

8 0
2 years ago
Read 2 more answers
A rectangular school banner has a length of 36 inches and a width of 52 inches. A sign is made that is similar to the school ban
zalisa [80]

Answer:

<u>4212 : 1573</u> is the ratio.

Step-by-step explanation:

Given:

Length of rectangular school banner is 36 inches and width is 52 inches.

And, the sign made is similar to banner.

The sign's length is 22 inches.

Now, we have to find the ratio of the area of the banner to the area of the sign.

So, we have dimensions of rectangular school banner:

Length = 36 inches.

Width = 52 inches.

But, we have only length of sign:

Length = 22 inches.

Now, we have to find the width of sign by using cross multiplication method:

Let the width of sign be x.

<em>As, sign is similar to banner.</em>

So, if 36 inches is equivalent to 52 inches.

Then, 22 inches is equivalent to x.

\frac{36}{52} =\frac{22}{x}

<em>By cross multiplying we get:</em>

<em />36x=1144<em />

<em>Dividing both sides by 36 we get:</em>

x=31\frac{7}{9} .

<em>Hence, the width of sign is </em>31\frac{7}{9}<em> inches.</em>

Now, we find the area of banner and the area of sign by putting formula:

Area of banner = length × width.

Area\ of\ banner=36\times 52

Area\ of\ banner=1872\ square\ inches.

Now, area of sign:

Area\ of\ sign=length\times width\\\\Area\ of\ sign=22\times 31\frac{7}{9} \\\\Area\ of\ sign=22\times \frac{286}{9} \\\\Area\ of\ sign=\frac{6292}{9} \ square\ inches.

Now, to get the ratio of the area of the school banner to the area of the sign:

1872:\frac{6292}{9}

=\frac{1872}{\frac{6292}{9} } \\\\=\frac{16848}{6292}

<em>On simplifying we get:</em>

=\frac{4212}{1573}

=4212:1573.

Therefore, the ratio of the area of the school banner to the area of the sign is 4212:1573.

8 0
3 years ago
Michele wanted to measure the height of her school’s flagpole. She placed a mirror on the ground 48 feet from the flagpole, then
yulyashka [42]
Height of the flagpole = x
distance from flagpole to the mirror = 48 ft
height of Michele = 5 ft
distance from Michele to the mirror = 12 ft

Now, set the proportion.

x/48 = 5/12
48 * x/48 = 5/12 * 48
x = 240/12
x = 20

So, the height of the flagpole is 20 ft.

HOPE THIS HELPS!!!!
5 0
3 years ago
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