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inessss [21]
3 years ago
14

Solve each equation with a variable 7X -14+ 2X equals negative 2X +3

Mathematics
1 answer:
Len [333]3 years ago
4 0

Answer:

7x - 14 + 2x =  - (2x + 3 )\\  \\ 9x - 14 =  -2x  -  3 \\  \\ 9x + 2x =  - 3  + 14 \\  \\ 11x = 11 \\  \\ { \underline{ \:  \: x = 1 \:  \: }}

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ValentinkaMS [17]

Answer:

P = 74

Step-by-step explanation:

14 + 60 = 74

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4 years ago
What is the answer to or help me learn what 54-6÷2+6=
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From: Dark Angel
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3 years ago
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6z^2-48x-120/3z^2+6z • 14z^5+140z^4/4z^2-400 =7z^3 Which values of s make the resulting expression undefined?
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3 years ago
Demand The demand function for a product is given by
stira [4]

Answer:

x= -\frac{ln [\frac{5P}{8000-P}]}{0.002}

a) x= -\frac{ln [\frac{5*200}{8000-200}]}{0.002} =1027.062 \approx 1027

b) x= -\frac{ln [\frac{5*800}{8000-800}]}{0.002} =293.893 \approx 294

Step-by-step explanation:

For this case we have the following function:

P= 8000 (1- \frac{5}{5 +e^{-0.002 x}})

We can solve for x like this. First we can reorder the expression like this:

\frac{P}{8000} = 1- \frac{5}{5+e^{-0.002x}}

\frac{5}{5+e^{-0.002x}} = 1 -\frac{P}{8000} = \frac{8000-P}{8000}

\frac{40000}{8000-P} = 5 + e^{-0.002x}

Now we can apply natura log on both sids and we got:

ln[\frac{40000}{8000-P} -5] = ln e^{-0.002x}

ln [\frac{5P}{8000-P}] = -0.002x

And if we solve for x we got:

x= -\frac{ln [\frac{5P}{8000-P}]}{0.002}

Part a

For this case we can replace P = 200 and see what we got for x like this:

x= -\frac{ln [\frac{5*200}{8000-200}]}{0.002} =1027.062 \approx 1027

Part b

For this case we can replace P = 800 and see what we got for x like this:

x= -\frac{ln [\frac{5*800}{8000-800}]}{0.002} =293.893 \approx 294

4 0
3 years ago
Which graph shows a linear function
kari74 [83]

Answer:

Graph B

Step-by-step explanation:

Linear functions are straight lines.

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