Answer:
Step-by-step explanation:
The rate at which the ice changes is -3/8 lb per hr
<h3>What is the rate the ice changes?</h3>
The given parameters are:
Changes =1 3/4 lb to 1/4 lb
Time = 1/4 hr.
The rate the ice changes is calculated as:
Rate = Change/Time
So, we have
Rate = (1/4 lb - 1 3/4 lb)/(1/4 hr)
Evaluate the difference
Rate = (-1 1/2 lb)/(1/4 hr)
Evaluate the quotient
Rate = -3/8 lb per hr
Hence, the rate at which the ice changes is -3/8 lb per hr
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Answer:
A = $10,441.68
A = P + I where
P (principal) = $10,400.00
I (interest) = $41.68
Step-by-step explanation:
First, convert R as a percent to r as a decimal
r = R/100
r = 0.02/100
r = 0.0002 rate per year,
Then solve the equation for A
A = P(1 + r/n)nt
A = 10,400.00(1 + 0.0002/2)(2)(20)
A = 10,400.00(1 + 0.0001)(40)
A = $10,441.68
Summary:
The total amount accrued, principal plus interest, with compound interest on a principal of $10,400.00 at a rate of 0.02% per year compounded 2 times per year over 20 years is $10,441.68.
Total is just add
n+16 is total of 16 and n
