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butalik [34]
3 years ago
7

Which property is demonstrated below?

Mathematics
1 answer:
Rom4ik [11]3 years ago
3 0
The answer is distributive property .
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The product of two integers is 112. One number is four more than three times the other. Which of the following equations could b
shepuryov [24]

Answer:

The  equations could be used to find one of the numbers is, 3a^2 + 4a =112

Step-by-step explanation

Let two integers be a and b.

As per the given statement:

The product of two integers is 112.

⇒  ab =112          ......[1]

Also, One number is 4 more than three times the other.

⇒b = 3a +4                      ......[2]

Now substitute equation [1] in [2] we get

a(3a+4) =112

Using distributive property i.e, a \cdot (b+c) = a\cdot b + a\cdot c

(a)(3a)+ 4a = 112

Simplify:

3a^2 + 4a =112

therefore, the equation that could be used to find one of the numbers is;

3a^2 + 4a =112


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If a polynomial is divided by x minus 5​, the quotient is 2 x squared plus 7 x minus 7 and the remainder is 7. Find the original
OlgaM077 [116]

Answer:

The original polynomial is 2x^3-3x^2-42x+42.

Step-by-step explanation:

The division of polynomial is analogue to the division of integers or natural numbers. For example, if we divide 25 by 6, we obtain that 4 is the quotient and the remainder is 1. We can recover 25 as 25 = 6*4+1.

Then, with this particular case, if we denote by P(x) the original polynomial, we have:

P(x) = (x-5)(2x^2+7x-7)+7.

Expanding the above multiplication:

P(x) = = 2x^3-3x^2-42x+42.

In general, given a polynomial P(x), if we divide it by another polynomial Q(x) (the divisor), there exist polynomials S(x) (the quotient) and R(x) (the remainder) such that

P(x) = Q(x)S(x) + R(x).

4 0
3 years ago
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