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3 years ago

5

Joe had read 140 pages of his 300 page book.what percent of the book has he read?

2 answers:

Nadusha1986 [10]3 years ago

5 0

But to work out this answer you do 140/300 then times the answer by 100 to get 46.6667 (or 47%)

Sergio [31]3 years ago

3 0

46.66% or rounded up 47%

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How do you find the property of 34 + 0 + 18 + 26 using Common Core math?

Flauer [41]

I assume you're looking for the sum.

I would use the null property to eliminate 0
34+0+18+26
=34+18+26
then use commutativity to rearrange
=34+26 + 18
Add 34+26=60
=60+18
=78

8 0

3 years ago

Put these numbers in order from least to greatest 1/8, -0.333, -1/7

Gekata [30.6K]

Answer:

-0.333, -1/7, 1/8

Step-by-step explanation:

1/8 is the greatest because it is a positive number while the other two numbers are negative.

-0.333 or -1/3 is smaller than -1/7.

7 0

1 year ago

Given tan theta =9, use trigonometric identities to find the exact value of each of the following:_______

Ludmilka [50]

Answer:

$(a)\ \sec^2(\theta) = 82$

$(b)\ \cot(\theta) = \frac{1}{9}$

$(c)\ \cot(\frac{\pi}{2} - \theta) = 9$

$(d)\ \csc^2(\theta) = \frac{82}{81}$

Step-by-step explanation:

Given

$\tan(\theta) = 9$

Required

Solve (a) to (d)

Using tan formula, we have:

$\tan(\theta) = \frac{Opposite}{Adjacent}$

This gives:

$\frac{Opposite}{Adjacent} = 9$

Rewrite as:

$\frac{Opposite}{Adjacent} = \frac{9}{1}$

Using a unit ratio;

$Opposite = 9; Adjacent = 1$

Using Pythagoras theorem, we have:

$Hypotenuse^2 = Opposite^2 + Adjacent^2$

$Hypotenuse^2 = 9^2 + 1^2$

$Hypotenuse^2 = 81 + 1$

$Hypotenuse^2 = 82$

Take square roots of both sides

$Hypotenuse =\sqrt{82}$

So, we have:

$Opposite = 9; Adjacent = 1$

$Hypotenuse =\sqrt{82}$

Solving (a):

$\sec^2(\theta)$

This is calculated as:

$\sec^2(\theta) = (\sec(\theta))^2$

$\sec^2(\theta) = (\frac{1}{\cos(\theta)})^2$

Where:

$\cos(\theta) = \frac{Adjacent}{Hypotenuse}$

$\cos(\theta) = \frac{1}{\sqrt{82}}$

So:

$\sec^2(\theta) = (\frac{1}{\cos(\theta)})^2$

$\sec^2(\theta) = (\frac{1}{\frac{1}{\sqrt{82}}})^2$

$\sec^2(\theta) = (\sqrt{82})^2$

$\sec^2(\theta) = 82$

Solving (b):

$\cot(\theta)$

This is calculated as:

$\cot(\theta) = \frac{1}{\tan(\theta)}$

Where:

$\tan(\theta) = 9$ ---- given

So:

$\cot(\theta) = \frac{1}{\tan(\theta)}$

$\cot(\theta) = \frac{1}{9}$

Solving (c):

$\cot(\frac{\pi}{2} - \theta)$

In trigonometry:

$\cot(\frac{\pi}{2} - \theta) = \tan(\theta)$

Hence:

$\cot(\frac{\pi}{2} - \theta) = 9$

Solving (d):

$\csc^2(\theta)$

This is calculated as:

$\csc^2(\theta) = (\csc(\theta))^2$

$\csc^2(\theta) = (\frac{1}{\sin(\theta)})^2$

Where:

$\sin(\theta) = \frac{Opposite}{Hypotenuse}$

$\sin(\theta) = \frac{9}{\sqrt{82}}$

So:

$\csc^2(\theta) = (\frac{1}{\frac{9}{\sqrt{82}}})^2$

$\csc^2(\theta) = (\frac{\sqrt{82}}{9})^2$

$\csc^2(\theta) = \frac{82}{81}$

4 0

3 years ago

I suck at math I need help with it!

muminat

Answer:

ok, I can help. Where's the math problem ?

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

If s ( x ) = 2 - x² and t ( x ) = 3x, what is s ( t ( -7 ) )?

ankoles [38]

Answer:

s (t (-7))=?

Step-by-step explana

s (t (-7))= -7s t

5 0

3 years ago