Any odd number can be expressed by 2n+1.
For example,
2n+1=111
2n=110
n=110/2=55
means that 111 is 2n+1 for n=55
Thus if an odd number is 2a+1, the next few numbers are as follows:
2a+1, 2a+2, 2a+3, 2a+4, 2a+5
So 2a+1, 2a+3 and 2a+5 are 3 consecutive odd numbers.
Back to our problem:
three consecutive odd numbers whose sum is 63 are:
(2n+1)+(2n+3)+(2n+5)=63
6n+9=63
6n=63-9=54
n=54/6=9
2n+1=2*9+1=18+1=19, the 2 next odd numbers are 21 and 23
Answer: 19, 21, 23
Answer: Write a quadratic function in vertex form whose graph has the vertex (1,2) and passes through the point (3,10). (what does F(x)=?) Algebra -> Quadratic Equations and Parabolas -> SOLUTION: Write a quadratic function in vertex form whose graph has the vertex (1,2) and passes through the point (3,10).
Step-by-step explanation:
Answer:
2 and 2 1/2
Step-by-step explanation:
3*3/4 = 9/4 This is slightly greater than 2
It lies between 2 and 2 1/2
Answer:
The correct statement would be: The positive number is 1/2 unit less than the opposite of the negative number.
Step-by-step explanation:
All stamemts are true except for the last one:
<em>The positive number is 1/2 unit more than the negative number.</em>
We can see in the plot that 1.5 is above zero and -2 is below zero.
So, -2<1.5
The opposite number of -2 is 2 and we can see that opposite number is 1/2 greater than 1.5. So, -2<1.5<2
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