All categories

3 years ago

PLease help me with this!

Mathematics

1 answer:

astraxan [27]3 years ago

6 0

Answer:

1. x2 - 9 > 0

x^2-3^2>0

(x+3)(x-3)>0

(x+3)>0 and (x-3)>0

x>-3 and x>3

2. x2 - 8x + 12 > 0

x^2 - 8x +12>0

x^2 -2x -6x +12 >0 (-8x is replaced by (-2x) + (-6x) )

x(x-2) -6(x-2) >0

(x-6)(x-2)>0

(x-6)>0 and (x-2)>0

x>6 and x>2

3. -x2 - 12x - 32 > 0

-x^2 -12x -32 >0

x^2 +12x +32 <0

x^2 +4x +8x +32<0

x(x+4) +8(x+4)<0

(x+8)(x+4)<0

(x+8)<0 and (x+4)<0

x<-8 and x<-4

4. x2 + 3x - 20 >= 3x + 5

x^2 +3x -20 >= 3x +5

x^2 +3x -20 -3x >= 3x +5 -3x

x^2 -20 >= 5

x^2 -20 +20 >= 5 +20

x^2 >=25

x^2-25 >=0

(x-5)(x+5)>=0

(x-5)>=0 and (x+5)>=0

x>=5 and x>=-5

You might be interested in

Which of the following gives all of the sets that contain -1/2?

Natalka [10]

Answer:

B the set of all natural numbers and the ser of all

7 0

3 years ago

Read 2 more answers

A= [2, 3; 2, 1], B=[3; 5]. Find AB & BA if possible

oksano4ka [1.4K]

Answer:

The value of AB is $\left[\begin{array}{ccc}21\\11\end{array}\right]$ and it's not possible to multiply BA.

Step-by-step explanation:

Consider the provided matrices.

$A=\left[\begin{array}{ccc}2&3\\2&1\end{array}\right]$ , $B=\left[\begin{array}{ccc}3\\5\end{array}\right]$

Two matrices can be multiplied if and only if first matrix has an order m × n and second matrix has an order n × v.

Multiply AB

Matrix A has order 2 × 2 and matrix B has order 2 × 1. So according to rule we can multiply both the matrix as shown:

$AB=\left[\begin{array}{ccc}2&3\\2&1\end{array}\right] \left[\begin{array}{ccc}3\\5\end{array}\right]$

$AB=\left[\begin{array}{ccc}2\times 3+3\times 5\\2\times 3+1\times 5\end{array}\right]$

$AB=\left[\begin{array}{ccc}6+15\\6+5\end{array}\right]$

$AB=\left[\begin{array}{ccc}21\\11\end{array}\right]$

Hence, the value of AB is $\left[\begin{array}{ccc}21\\11\end{array}\right]$

Now calculate the value of BA as shown:

Multiply BA

Matrix B has order 2 × 1 and matrix A has order 2 × 2. So according to rule we cannot multiply both the matrix.

We can multiply two matrix if first matrix has an order m × n and second matrix has an order n × v.

That means number of column of first matrix should be equal to the number of rows of second matrix.

Hence, it's not possible to multiply BA.

5 0

3 years ago

A diner has a breakfast special. A customer can chose scrambled, fried, or poached eggs. The breakfast comes with a side of baco

Kryger [21]

3x3x3=27

So, there are 27 combinations.

3 0

3 years ago

Read 2 more answers

Steven is taking out a loan in the amount of $5,000. His choices are a 3-year loan at 5% simple interest and a 5 -year loan at 4

Andre45 [30]

I do believe it’s 250$

**The first choice:**
Principal: 5,000$
Rate(%): 5
Time(year): 3 years
A: 5,750$

**Second choice**
Principal: 5,000$
Rate(%): 4%
Time(year): 5 years
A: 6,000$

6,000-5,750=250$

Hope this helps!

8 0

3 years ago

78/25 as a terminating decimal

Kazeer [188]

To write $\frac{78}{25}$ as a terminating decimal we will turn this fraction to a decimal. To do this we will divide the numerator by the deliminator and the result will be the decimal.Then we will check if it is a terminating decimal or repeating decimal. Lets do it:-

$\frac{78}{25}$
78 ÷ 25 = 3.12

3.12 is a terminating decimal.

So, $\frac{78}{25}$ as a terminating decimal is 3.12.

Hope I helped ya!!

8 0

3 years ago

Read 2 more answers