Answer:
2nd one. Albedo and positive
Explanation:
Anatomy During Contraction
-Sarcomere, itself, is shorter
-H-zone is shorter (part of A-band that doesn't have actin filaments in it)
-I-band gets shorter (part of sarcomere lacking myosin)
-A-band stays the same size (zone that contains myosin)
During binary fission in a bacterial cell, a base pair is changed from adenine to cytosine due to a random mutation.
Binary fission is a type of asexual reproduction through which a bacteria divides and its body is separated into two new bodies.
If during binary fission in a bacterial cell, a base pair is changed from adenine to cytosine, it is because of a random mutation. A mutation is a genetic alteration or a change in the DNA sequence which results in the generation of a variant. Mutations in the DNA sequence which occur without any specific pattern is known as a random mutation.
To learn more about mutation here
brainly.com/question/13923224
#SPJ4
Correct option b) A saturated fatty acid
When only one double bond in the molecules that is also known as monounsaturated fat. If there is more than one double bond that is known as polyunsaturated fat.
Unsaturated fatty acids have one or more than one carbon- carbon band double bonds. That indicates the maximum possible numbers of hydrogen atoms are bonds to each carbon in the molecule. These carbon form double bonds with the carbons next to them.
Alkenes contain carbon- carbon double bonds and unsaturated hydrocarbons with the molecular formula is Cn H2n. This is made of chains where some carbon atoms are not fully saturated with hydrogen atoms.
To learn more about polyunsaturated fat here
brainly.com/question/13141983
#SPJ4
Given: The systolic arterial blood pressure observed for 20 dogs is normally distributed with a mean of 152 mm of mercury (Hg) and a standard deviation of 18 mm of Hg.
To find: P(100 < 152)
Method: Calculation of Z-Score followed by the probability or area of the bell curve at X = 100.
Solution:
Mean u = 152, std s = 18
Z score = 
The value of P(100<152) is calculated by looking at the value of Z in the Z score for the standard normal distribution given in the image.
P(Z=-2.89) = 0.0019
The P(Z = -2.89) corresponds to the area in the left tail of the bell curve.
Thus the probability of 100 mm Hg blood pressure is 0.0019.
