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3 years ago

Algebra- pls help ;-; will mark brainliest

Mathematics

2 answers:

Pavlova-9 [17]3 years ago

7 0

Answer:

The solution is correct.

Sergio [31]3 years ago

6 0

Answer:

r = 9 is the correct solution..

the error was in the 2nd line where it should be -10+2r=8 instead of -10-2r=8

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Which expression is equivalent to 28 + 7? Prove your answer by showing your work.

OverLord2011 [107]

Answer:

ok so first lets find the answer to the original question

28+7=35

so lets find which one is equal to 35

7(4+1)=28+7=35 yes

4(7+1)=28+4=32 no

4(7+3)=28+12=40 no

7(4+7)=28+49=77 no

a is the answer

Hope This Helps!!!

6 0

3 years ago

ABSOLUTEEE VALUEEEE HELPP PLZ

morpeh [17]

Answer:

Last option; x < 2 and x > -1

Step-by-step explanation:

1. We know 2x − 1 < 3 and 2x − 1 > −3, so let's solve both of these inequalities.

2. (Solving for 1st condition)

Step 1: Add 1 to both sides.

$2x - 1 + 1 < 3 + 1$
$2x < 4$

Step 2: Divide both sides by 2.

$\frac{2x}{2} < \frac{4}{2}$
$x < 2$

3. (Solving for 2nd condition)

Step 1: Add 1 to both sides.

$2x - 1 + 1 > -3 + 1$
$2x > -2$

Step 2: Divide both sides by 2.

$\frac{2x}{2} > \frac{-2}{2}$
$x > -1$

4. Now, we know that the value of x is greater than -1 but less than 2, and we can represent it on a number line like this:

5 0

3 years ago

Read 2 more answers

If you multiply the slopes of two perpendicular lines, the product is −1. (As long as neither line is vertical.) Use that fact a

Troyanec [42]

Answer:

more information please

Step-by-step explanation:

5 0

4 years ago

Read 2 more answers

Determine for which values of m the function variant Φ(x) = x^m is a solution to the given equation. a. 3x^2 (d^2y/dx^2) + 11x(d

miv72 [106K]

Answer:

a) m = -9 or m = 1

b) m = 1 + √6 or m = 1 -√6

Step-by-step explanation:

for

Φ(x) = x^m

then

dΦ/dx (x) = m*x^(m-1)

d²Φ/dx² (x) = m*(m-1)*x^(m-2)

then

for a

3x^2 (d^2y/dx^2) + 11x(dy/dx) - 3y = 0

3x^2*m*(m-1)*x^(m-2) + 11*x* m*x^(m-1) - 3*x^m = 0

3*m*(m-1)*x^m + 11*m*x^m- 3*x^m = 0

dividing by x^m

3*m*(m-1) + 11*m - 3 =0

3*m² + 8 m - 3 =0

m= [-8 ± √(64 + 4*3*3)]/2 = (-8±10)/2

m₁ = -9 , m₂= 1

then Φ(x) = x^m is a solution for the equation a , when m = -9 or m = 1

for b)

x^2 (d^2y/dx^2) - x(dy/dx) - 5y = 0

x^2*m*(m-1)*x^(m-2) - x* m*x^(m-1) - 5*x^m = 0

m*(m-1)*x^m -m *x^m- 5*x^m = 0

dividing by x^m

m*(m-1) -m - 5 =0

m² - 2 m - 5 =0

m= [2 ± √(4 + 4*1*5)]/2 = (2±√24)/2 = 1 ±√6

m₁ = 1 + √6 , m₂ = 1 - √6

then Φ(x) = x^m is a solution for the equation b , when m = 1 + √6 or m = 1 - √6

7 0

3 years ago

Read 2 more answers

Consider the following binomial experiment:

Sedbober [7]

Answer:

0.624

Step-by-step explanation:

Given that:

Number of copiers with the company = 4

It is a binomial experiment.

Probability that on a given day, one copier will break down = $\frac{23}{50}$

$p = \frac{23}{50}$ = 0.46

$q = 1-p = 1-\frac{23}{50}= \frac{27}{50}$ = 0.54

<em>Formula for Binomial probability: </em>

$P(x=r) = _{n}C_{r}p^rq^{n-r}$

We have to find $P(x >= 2)$

$P(x >= 2) = P(X=2)+P(X=3)+P(X=4)$

$P(x=2) = _{4}C_{2}0.46^2\times 0.54^{2} = 0.37\\P(x=3) = _{4}C_{3}0.46^3\times 0.54 = 0.21\\P(x=4) = _{4}C_{4}0.46^4\times 0.54^{0} = 0.044$

$P(x >= 2) = 0.37 + 0.21 + 0.044 = \bold{0.624}$

4 0

3 years ago