Answer:
5 Days ....thats easy....
Hope this answer is correct ..
Have a nice day ahead
A.) For the Junior Varsity Team, mean would be the appropriate measure of center since the data is <span>symmetric or well-proportioned while we should use standard deviation for getting the measure of spread since it also measures the center and how far the values are from the mean.
b.) For the Varsity Team, the median would be the appropriate measure of the center since the data is skewed left and not evenly distributed so median could be used since it does not account for outliers while we use IQR or interquartile range in measuring the spread of data since IQR does not account for the data that is skewed. </span>
Answer:
Period=2pi/3
Step-by-step explanation:
Answer:
the awencer is 4.2
Step-by-step explanation:
Remark
It is not a straight line distance from the park to the mall. None of the answers give you that result. And if you know what displacement is, none of the answers are really displacement either. The distance is sort of a "as the crow flies." distance. There's a stop off in the middle of town.
Method
You need to use the Pythagorean Formula twice -- once from the park to the city Center and once from the city center to the mall.
Distance from the Park to the city center.
a = 3 [distance east]
b = 4 [distance south]
c = ??
c^2 = 3^2 + 4^2 Take the square root of both sides.
c = sqrt(3^2 + 4^2)
c = sqrt(9 + 16) Add
c = sqrt(25)
c = 5
So the distance from the park to the city center is 5 miles
Distance from City center to the mall
a = 2 miles [distance east]
b = 2 miles [distance north]
c = ??
c^2 = a^2 + b^2 Substitute
c^2 = 2^2 + 2^2 Expand this.
c^2 = 4 + 4
c^2 = 8 Take the square root of both sides.
sqrt(c^2) = sqrt(8)
c = sqrt(8) This is the result
c = 2.8
Answer
Total distance = 5 + 2.8 = 7.8
