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Doss [256]
3 years ago
10

Please refer to the attached picture. Answer it in English only.​

Computers and Technology
2 answers:
finlep [7]3 years ago
8 0

Answer:

the advantages of database in 5 points are as follows

Explanation:

Data Integrity. Data integrity means data is consistent and accurate in the database. ...

Data Security. Data security is a vital concept in a database. ...

Better data integration. ...

Minimized Data Inconsistency. ...

Faster Data Access. ...

Better decision making. ...

Simplicity. ...

Recovery and Backup.

Shtirlitz [24]3 years ago
3 0

Here are Few advantages of databases

  • Better Data Transference.
  • Extra Data security.
  • Minimum or minimized data inconsistency .
  • Solid data integration.
  • Very fast access to data.
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Create an application named TestClassifiedAd that instantiates and displays at least two ClassifiedAd objects. A ClassifiedAd ha
arlik [135]

Answer:

Following is given the code with all necessary descriptions as comments in it. The output is also attached under the code. I hope it will help you!

Explanation:

5 0
3 years ago
What is the best way to beat someone on starve.io? with a lava sword, or a pirate sword.
makkiz [27]

Answer:

Lava sword all the way

Explanation:

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8 0
3 years ago
Modify the countUp( ) you wrote in the previous question to countUp( num), where num is a parameter. The function displays from
algol [13]

Answer:

void countUp(int num)

{

   if(num==0) //base case.

   return;

   countUp(num-1);//Recursive call.

   cout<<num<<" "; //printing the number.

}

for input num=25

Output:-1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25

Explanation:

I have used recursion to print the numbers the function is in c++ language.In every recursive call we are decreasing num by 1.As the base case is reached.Then it will backtrack from 1 to num and then we are printing while backtracking.

4 0
4 years ago
In a system with paging as the address translation mechanism, using multi-level paging always causes less memory usage for stori
Zarrin [17]

Answer:

The given statement is "True". A further explanation is given below.

Explanation:

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3 0
3 years ago
You should also create a method named canBoardTogether which determines if passengers already in line in the tickets ArrayList c
qaws [65]

Answer:

See explaination

Explanation:

import java.util.ArrayList;

public class Main

{

public static void main(String[] args)

{

ArrayList<AirlineTicket> tickets = new ArrayList<AirlineTicket>();

//This creates a randomized list of passengers

addPassengers(tickets);

for(AirlineTicket elem: tickets)

{

System.out.println(elem);

}

//This creates a TicketOrganizer object

TicketOrganizer ticketOrganizer = new TicketOrganizer(tickets);

//These are the methods of the ticketOrganizer in action

System.out.println("\nPassengers Ordered by Boarding Group:");

ticketOrganizer.printPassengersByBoardingGroup();

System.out.println("\nPassengers in line who can board together:");

ticketOrganizer.canBoardTogether();

}

//Do not touch this method! It is adding random passengers to the AirlineTicket array

public static void addPassengers(ArrayList<AirlineTicket> tickets)

{

String[] seats = {"A","B","C","D","E","F"};

for(int index = 0; index< 15; index++)

{

int random = (int)(Math.random() * 5);

AirlineTicket ticket = new AirlineTicket("Passenger " + (index+1), seats[random], ((int)(Math.random()*5)+1), ((int)(Math.random()*8)+1));

tickets.add(ticket);

}

}

}

class TicketOrganizer

{

private ArrayList<AirlineTicket> tickets ;

//constructor with parameter as an arraylist of AirlineTicket

public TicketOrganizer(ArrayList<AirlineTicket> tickets)

{

this.tickets = tickets;

}

//methhods to return the arraylist of airlines

public ArrayList<AirlineTicket> getTickets()

{ //re-organize the ticket first

ArrayList<AirlineTicket> tickets_organized = new ArrayList<AirlineTicket>();

for(int i=1; i<=5; i++)

{

for(AirlineTicket ticket: tickets)

{

if(ticket.getBoardingGroup() == i)

{

tickets_organized.add(ticket);

}

}

}

return tickets_organized;

}

//print the tickets based on boardingGroup

public void printPassengersByBoardingGroup()

{

int count = 0;

for(int i=1; i<=5; i++)

{

System.out.println("Boarding Group " + i + ":");

for(AirlineTicket ticket : tickets)

{

if(ticket.getBoardingGroup() == i)

{

System.out.println("Passenger " + ticket.getName());

}

}

}

}

//check if two persons can sit together

public void canBoardTogether()

{

for(int i=0; i<15; i++)

{

String str = "Passenger "+ (i + 1) +" can board with Passengers";

for(int j=i+1; j<14; j++)

{

boolean isRowEqual = tickets.get(i).getRow() == tickets.get(j).getRow();

boolean isBoardGroupEqual = tickets.get(i).getBoardingGroup() == tickets.get(j).getBoardingGroup();

//if one of them false, print the all added Passengers

if(!(isRowEqual && isBoardGroupEqual))

{

if(j != i+1)

{

System.out.println(str);

}

break;

}

str += " " + (j+1);

}

}

}

}

class AirlineTicket

{

private String[] seats = {"A","B","C","D","E","F"};

private String name;

private String seat;

private int boardingGroup;

private int row;

public AirlineTicket(String name, String seat, int boardingGroup, int row)

{

this.name = name;

if(isValidSeat(seat))

{

this.seat = seat;

}

this.boardingGroup = boardingGroup;

this.row = row;

}

private boolean isValidSeat(String seat)

{

boolean isValidSeat = false;

for(String elem: seats)

{

if(seat.equals(elem))

{

isValidSeat = true;

}

}

return isValidSeat;

}

public String getSeat()

{

return this.seat;

}

public String getName()

{

return this.name;

}

public int getBoardingGroup()

{

return this.boardingGroup;

}

public int getRow()

{

return this.row;

}

public String toString()

{

return name + " Seat: " +seat + " Row: " + row + " Boarding Group: " + boardingGroup;

}

}

3 0
3 years ago
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