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Leokris [45]
3 years ago
5

The henry's law constant (k) for carbon monoxide in water at 25°c is 9. 71  10-4 mol/(l·atm). How many grams of co will dissolv

e in 1. 00 l of water if the partial pressure of co is 2. 75 atm?.
SAT
1 answer:
Triss [41]3 years ago
8 0
I’ve never seen this
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Drag the labels to their appropriate locations on the table below. Targets in Group 1 refer to the phenotypes, targets in Group
muminat

The label match up are:

  • dark fur
  • more individuals with darker fur
  • dark rocks and light rocks
  • dark fur and light fur
  • rocks of intermediate color
  • more individuals with intermediate fur color

<h3>What is a phenotype?</h3>

A person's Phenotype is known to be those detectable qualities or traits of their genotype.

Looking at the image, the label match up are:

  • dark fur
  • more individuals with darker fur
  • dark rocks and light rocks
  • dark fur and light fur
  • rocks of intermediate color
  • more individuals with intermediate fur color

Learn more about phenotypes from

brainly.com/question/902712

#SPJ1

7 0
2 years ago
Unit 11 volume &amp; surface area homework 5 surface area of prisms &amp; cylinders
likoan [24]

The volume of the prism is the amount of space on the prism

The volume of the cylinder is 760 cubic units

<h3>How to determine the volume?</h3>

The question is incomplete.

So, we make use of the following parameters

  1. Shape = Cylinder
  2. Radius, r = 11
  3. Height, h = 2.

The volume of a cylinder is calculated using:

V = πr²h

Substitute known values in the above formula

V = 3.14 * 11² * 2

Evaluate the product

V = 759.88

Approximate

V = 760

Using the assumed values, the volume of the cylinder is 760 cubic units

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7 0
2 years ago
MUSIC HELP plss ahh pls
Mashutka [201]

Answer:

THERE'S A 15 NOTE COUNTS

4 0
2 years ago
A dress which costs $180 is being soldata<br> discount of 10%. The amount of the<br> discount is
Dimas [21]

Answer:

162$ and savings would be 18 $

5 0
3 years ago
Read 2 more answers
For 2-methylbutane, the ∆h° of vaporization is 25. 22 kj/mol and the ∆s° of vaporization is 84. 48 j/mol・k. At 1. 00 atm and 201
pogonyaev

The Gibbs free energy ΔG for the vaporisation of 2-methylbutane, in KJ/mol is 8.24 KJ/mol

<h3>Data obtained from the question </h3>
  • Enthalpy change (ΔH) = 25. 22 KJ/mol
  • Change in entropy (ΔS) = 84.48 J/Kmol = 84.48 / 1000 = 8.448×10¯² KJ/Kmol
  • Temperature (T) = 201 K
  • Gibbs free energy (ΔG) =?

<h3>How to determine the Gibbs free energy </h3>

The Gibbs free energy for the reaction can be obtained as follow:

ΔG = ΔH – TΔS

ΔG = 25.22 – (201 × 8.448×10¯²)

ΔG = 25.22 – 169.8048

ΔG = 8.24 KJ/mol

Thus, the ΔG for the reaction is 8.24 KJ/mol

Learn more about Gibbs free energy:

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7 0
3 years ago
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