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kari74 [83]
3 years ago
15

Can’t figure this out, I keep getting it wrong

Mathematics
1 answer:
uysha [10]3 years ago
6 0
Two units, count the squares. Random letters because minimum word count
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use benchmarks to determine the costomaryand metric units you would use to measure the height of your house. explain your answer
SVEN [57.7K]
What are the words? there are no words being showed.
5 0
3 years ago
Need help with number 3 inequalities with variables on both sides
Volgvan

Answer:

x ≤ 2

Step-by-step explanation:

We are given the inequality:

\displaystyle{2x-3 \leq \dfrac{x}{2}}

First, get rid of the denominator by multiplying both sides by 2:

\displaystyle{2x\cdot 2-3\cdot 2 \leq \dfrac{x}{2}\cdot 2}\\\\\displaystyle{4x-6 \leq x}

Add both sides by 6 then subtract both sides by x:

\displaystyle{4x-6+6 \leq x+6}\\\\\displaystyle{4x \leq x+6}\\\\\displaystyle{4x-x \leq x+6-x}\\\\\displaystyle{4x-x \leq 6}\\\\\displaystyle{3x \leq 6}

Then divide both sides by 3:

\displaystyle{\dfrac{3x}{3} \leq \dfrac{6}{3}}\\\\\displaystyle{x \leq 2}

Therefore, the answer is x ≤ 2

5 0
2 years ago
Read 2 more answers
The figure here shows triangle AOC inscribed in the region cut from the parabola y=x^2 by the line y=a^2. Find the limit of the
aleksandrvk [35]
Area of the parabolic region = Integral of [a^2 - x^2 ]dx | from - a to a =

(a^2)x - (x^3)/3 | from - a to a = (a^2)(a) - (a^3)/3 - (a^2)(-a) + (-a^3)/3 =

= 2a^3 - 2(a^3)/3 = [4/3](a^3)

Area of the triangle = [1/2]base*height = [1/2](2a)(a)^2 = <span>a^3

ratio area of the triangle / area of the parabolic region = a^3 / {[4/3](a^3)} =

Limit of </span><span><span>a^3 / {[4/3](a^3)} </span>as a -> 0 = 1 /(4/3) = 4/3
</span>
 



3 0
3 years ago
"Expand the brackets and Simplify"<br>(pls i need help asap)​
givi [52]
A) 2(1+2c)

2+4c = 2+4c

B) 6(14r-2t)

= 84r-12t
6 0
3 years ago
Help plzzzzzzzzzzzzzzzzz
Butoxors [25]

Answer:

6 % is the answer

Step-by-step explanation:

6.50 x 6%=0.39

6.50+0.39=6.89

4 0
3 years ago
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