What is 7 x 10^2 power in STANDARD FORM

Mathematics

1 answer:

olya-2409 [2.1K]3 years ago

5 0

Answer:

700

Step-by-step explanation:

7x=2+10

7x=12

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Solveeee both i neeeeeedddd hellllpppp

SCORPION-xisa [38]

Short answer: C
Remark
Since b is all by itself in equation 2, Substitute it into equation 1.

2a + 3b = 5
b = a - 5 Put this result in equation 1. Be sure and use brackets.
2a + 3(a - 5) = 5 Remove the brackets.
2a + 3a - 15 = 5 Notice the -5 inside the brackets becomes - 15
Combine like terms on the left.
5a - 15 = 5 Add 15 to both sides
5a = 5 + 15
5a = 20 Divide by 5
a = 20/5
a = 4

So far, c is the only possible answer.
b = a - 5
b = 4 - 5
b = - 1

5 0

3 years ago

In a recent survey of monetary donations made by college graduates, the following information was obtained: 91 graduates had don

vodka [1.7K]

Answer: a) 11.26% and b) 50.23%

Step-by-step explanation:

Number of graduates donated to a political campaign n(A) = 91

Number of graduates donated to assist medical research n(B) = 76

Number of graduated to help preserve the environment n(C) = 131

Number of graduated donated to all n(A∩B∩C) = 27

Number of graduates donated to none = 24

Number of graduated donated to political campaign and to medical research n(A∩B) = 32

Number of graduates donated to medical research and to preserve the environment n(B∩C) = 48

Number of graduates donated to a political campaign and to preserve the environment n(C∩A) = 56

Now,

n(U)=n(A)+n(B)+n(C)-n(A∩B)-n(B∩C) -n(C∩A)+n(A∩B∩C)+n(none)

$n(U)=91+76+131-32-48-56+27+24=213$

So, What percent of the college graduates donated to none of the three listed causes?

Percentage would be

$\dfrac{24}{213}\times 100\\\\=11.26\%$

(b) What percent of the college graduates donated to exactly one of the three listed causes?

Exactly one = 91+76+131-2(32-56-48)+3(27)=107

Percentage would be

$\dfrac{107}{213}\times 100\\\\=50.23\%$

Hence, a) 11.26% and b) 50.23%

4 0

4 years ago

an open box with a square base have a volume of 8m^3. the material of the base costs $8 per square meter and the material for th

max2010maxim [7]

(Refer to picture for diagram.)

Area of base $=w^{2}$
Area of one side $=\frac{8}{w^{2}}*w=\frac{8}{w}$

Cost of base material $=8w^{2}$
Cost of material for a side $=6*\frac{8}{w}=\frac{48}{w}$
There are 4 sides so $4*\frac{48}{w}=\frac{192}{w}$

Total cost $C(w)=8w^{2}+\frac{192}{w}$