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3 years ago

Raiz quadrada de 999999

Mathematics

1 answer:

Neko [114]3 years ago

6 0

Answer:

raiz quadrada de 999999 = 999.999499899

raiz quadrada de 999999 = 999.999499899.

Hopefully it will help you

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Is this right pls tell me FOR BRAINLIES RATE AND FOLLOW

Elenna [48]

Yes this is correct great job!

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3 years ago

Find sum of 100, 50, 25, 12.5

levacccp [35]

Add all the numbers together:

100+50= 150

150+25= 175

175+12.5= 187.5

187.5 is the sum.

I hope this helps!

5 0

3 years ago

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Given a function described as equation y=3x+4, what is y when x is 1,2 and 3?

koban [17]

Answer:

x=1 y= 7

x=2 y= 10

x=3 y= 13

Step-by-step explanation:

y=3x+4

y=3(1)+4

y=3(2)+4

=-10

y=3(3)+4

=13

4 0

3 years ago

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Solve the inequalities; 1. |4x + 5| + 2 ≥ 10 2. |2x + 3| + 6 > 0

slamgirl [31]

Answer:

Number two: x > -9/2, x < 3/2

Number one: x is less than or equal to 3/4, x is greater than or equal to - 13/4

Step-by-step explanation:

Number one:

|4x+5| > 10-2

|4x+5| > 8

4x+5 > 8

-(4x+5) > 8

x > 3/4

x < -13/4

x > 3/4, x < -13/4

(all of these signs are greater than or equal to and less than or equal to)

Number two:

|2x+3| > -6

2x+3 > -6

-(2x+3) > -6

x > -9/2

x < 3/2

x> -9/2, x < 3/2

(all of these signs are correct and not greater than or equal to or less than or equal to)

7 0

3 years ago

A bag contains eleven equally sized marbles, which are numbered. Two marbles are chosen at random and replaced after each select

Digiron [165]

Answer:

B. $\frac{24}{121}$ .

Step-by-step explanation:

Total number of marbles = 11.

Since, after choosing the first marble, we are putting it back and then the second marble is chosen.

As, there are 4 shaded marbles.

So, the probability of getting the first marble shaded = $\frac{\binom{4}{1}}{\binom{11}{1}}$ = $\frac{4}{11}$

Also, there are 6 odd labeled marbles.

So, the probability of getting the second marble being odd labeled = $\frac{\binom{6}{1}}{\binom{11}{1}}$ = $\frac{6}{11}$

So, the probability of getting the first marble shaded and second marble labeled odd = $\frac{4}{11}\times \frac{6}{11}$ = $\frac{24}{121}$ .

Hence, the required probability is $\frac{24}{121}$ .

4 0

3 years ago

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