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2 answers:
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Answer:
Step-by-step explanation:
The question lacks the required diagram. Find the diagram attached below;
According to the first triangle, taking 30° as the reference angle, the opposite side of the triangle will be 5 and the adjacent will be the unknown side "b"
According to SOH, CAH, TOA;
tanθ = opposite/adjacent (using TOA)
Given;
θ = 30°, opposite = 5 and adjacent = b
tan30° = 5/b
b = 5/tan30°
b = 5/(1/√3)
b = 5*√3/1
b = 5√3
According to the 45° triangle, the opposite side of the triangle will be d and the hypotenuse will be 7
Using SOH;
sinθ = opposite/hypotenuse
Given;
θ = 45°, opposite = d and adjacent = 7
sin45° = d/7
d = 7sin45°
d = 7(1/√2)
d = 7/√2
Rationalize 7/√2
= 7/√2*√2/√2
=7√2/2
Hence the value of d is 7√2/2
Answer with Step-by-step explanation:
We are given that if sum of several numbers is odd
We have to prove that at least one of the number is itself odd.
Suppose, we have three numbers
a=6 , b=7,d=8
Sum of numbers=6+7+8=21=Odd number
We know that sum of two odd numbers is always an even number.
Sum of an odd number and an even number is always an odd number.
If we take even odd numbers then sum is always an even number and sum of odd odd numbers then the sum is always an odd number.
Sum of even numbers is always an even number.
Hence, there are atleast one numebr is odd then the sum of several number is odd.