Q - 23 when q = 71 this is evaluating expressions

Mathematics

1 answer:

-BARSIC- [3]2 years ago

3 0

71 - 23 = 48 is the answer

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What is answer for 10+(3+4-6+8) by using order of operation

Zina [86]

Answer:

The value of given expression is 19.

Step-by-step explanation:

The given expression is

$10+(3+4-6+8)$

According to the rule of BODMAS the order of operations is Bracket, Of, Division, Multiplication, Addition and Subtraction.

First we have to simplify the value of bracket.

$10+(3+4-6+8)=10+(15-6)$

$10+(3+4-6+8)=10+9$

$10+(3+4-6+8)=19$

Therefore the value of given expression is 19.

3 0

3 years ago

Read 2 more answers

Ok so i have to write something

kap26 [50]

(11/3-7/4)/[3.4-(1/2+2/3*3/2)]

First I converted fractions to mixed numbers.

11/3-7/4 / 3.4-3/2

Then, I solve the inside of the parentheses.

23/12 / 3.4-3/2

Continue to simplify

Convert to decimals

1.91667/1.9

Hope this helps

6 0

2 years ago

Find the complex zeros of x^3+27. write f in factored form

aliina [53]

$x^3+27=0
\\x^3+3^3=0
\\(x+3)(x^2-3x+9)=0
\\x^2-3x+9=0
\\a=1,b=-3,c=9
\\
\\x_{1,2}= \frac{-b\pm \sqrt{b^2-4ac} }{2a} = \frac{-(-3)\pm \sqrt{(-3)^2-4\times1\times9} }{2\times1} =\frac{3\pm \sqrt{-27} }{2} =\frac{3\pm 3\sqrt{3}i }{2} 
\\
\\(x+3)(x-\frac{3+ 3\sqrt{3}i }{2})(x-\frac{3- 3\sqrt{3}i }{2})=0

$