If you are asking for the area of the rectangle...
Let L = Length
Let W = Width
Let A = Area of rectangle
A = LW
A = ( 2x + 3 ) ( 4x - 1 )
A = 8x^2 - 2x + 12x - 3
A = 8x^2 + 10x - 3
If you are asking for the perimeter of the rectangle...
Let L = Length
Let W = Width
Let P = Perimeter of rectangle
P = 2L + 2W
P = 2 ( 2x + 3 ) + 2 ( 4x - 1 )
P = 4x + 6 + 8x - 2
Expanded form -
P = 12x + 4
Factorised form -
P = 4 ( 3x + 1 )
Hope this helps! :)
Have a lovely day! <3
Answer: Henry read for a total of 40 minutes
Step-by-step explanation: 3:00 - 0:50 is 2:10 then 2:10 - 1:30= 40 minutes
<span>step 1 :</span><span> 6
Simplify ——
x2
</span><span>Equation at the end of step 1 :</span><span> 10 6
(((((x2)+3x)-————)-2x)-15)——)+6x)+9)
(x2)(((((x^2)x2
</span><span>Step 2 :</span>Rewriting the whole as an Equivalent Fraction :
<span> 2.1 </span> Subtracting a fraction from a whole
Rewrite the whole as a fraction using <span> <span>x2</span> </span> as the denominator :
<span> x2 + x (x2 + x) • x2
x2 + x = —————— = —————————————
1 x2
</span>
<span>Equivalent fraction : </span>The fraction thus generated looks different but has the same value as the whole
<span>Common denominator : </span>The equivalent fraction and the other fraction involved in the calculation share the same denominator
<span>Step 3 :</span>Pulling out like terms :
<span> 3.1 </span> Pull out like factors :
<span> x2 + x</span> = x • (x + 1)
Adding fractions that have a common denominator :
<span> 3.2 </span> Adding up the two equivalent fractions
Add the two equivalent fractions which now have a common denominator
Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:
<span> x • (x+1) • x2 - (6) x4 + x3 - 6
———————————————————— = ———————————
x2 x2
</span><span>Equation at the end of step 3 :</span><span> 10 (x4+x3-6)
(((((x2)+3x)-————)-2x)-15)—————————+6x)+9)
(x2)(( x2
</span><span>Step 4 :</span>Rewriting the whole as an Equivalent Fraction :
<span> 4.1 </span> Adding a whole to a fraction
Rewrite the whole as a fraction using <span> <span>x2</span> </span> as the denominator :
<span> 6x 6x • x2
6x = —— = ———————
1 x2 </span>
The solution set of the given inequality has a domain of (-∞, ∞) and the vertex(h,k) = (1, -9)
<h3>What is the solution set for inequality?</h3>
The solution set for inequality is the set of all solutions for which the inequality is defined. It can also be represented in an interval notation.
Given that:
By rewriting the equation in the parabola standard form 4p(y-k) = (x - h)², we have:
Therefore, the parabola properties are:
- The solution set of the domain is (-∞, ∞)
- Vertex(h,k) = (1, -9)
- Focal length |p| = 1/4
Learn more about the solution set of inequality here:
brainly.com/question/1496731
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The number of diagonals in a polygon with n sides is 
So, in polygon with 14 sides, there is 
diagonals.
