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3 years ago

Break apart the addends to find the sum 33+49

Mathematics

1 answer:

ArbitrLikvidat [17]3 years ago

5 0

33+49
(30+40) + (3+9)
70 + 12
82

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David hikes 21/4 miles in 1/2 an hour. What is his rate in miles per hour? At this rate, how long will it take him to walk 18 mi

harkovskaia [24]

Answer:

A) speed = 10.5 miles per hour

B) Time taken by him = 1.714 hours

C) Distance = 10.5 mph × 7 hours = 73.5 miles

Step-by-step explanation:

Given as :

The distance cover by David = $\frac{21}{4}$ miles = 5.25 miles

The time taken by David = $\frac{1}{2}$ hours = 0.5 hours

Let the speed = x mile per hour

So, Distance = Speed × Time

A)or, Speed = $\frac{Distance}{Time}$

Or, Speed = $\frac{5.25}{0.5}$

∴ speed = 10.5 miles per hour

<u>B) Again The Distance cover by him = 18 miles</u>

SO, with speed 10.5 miles per hour

The Time taken by him = $\frac{Distance}{speed}$ hours

Or, Time taken by him = $\frac{18}{10.5}$ hours

∴ Time taken by him = 1.714 hours

<u>C) Again the Time taken by him = 7 hours </u>

So, Distance cover by him with speed 10.5 mph

Or, Distance = 10.5 mph × 7 hours = 73.5 miles

A) speed = 10.5 miles per hour

B) Time taken by him = 1.714 hours

C) Distance = 10.5 mph × 7 hours = 73.5 miles Answes

8 0

3 years ago

What is an equation of the parabola with vertex at the origin and focus (0, 0.75)?

morpeh [17]

Answer:

$x^{2} =3y$

Step-by-step explanation:

Notice that the focus is a points on the vertical axis, that means the parabolla opens vertically, and has the form

$x^{2} =4py$

Because the parameter $p$ is positive and equal to 0.75. Additionally, the vertex is at the origin, that's why the equation is this simple.

Replacing the parameter value, we have

$x^{2} =4(0.75)y\\x^{2} =3y$

Therefore, the equation of a parabolla with vertex at the origin and focus at (0, 0.75) is $x^{2} =3y$ .

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3 years ago

Shannon has 1 nickel, 2 dimes, and 5 unknown coins totaling $0.81. What kind of coins does Shannon have and how many are there o

AlekseyPX

Answer:

The 5 unknown are 1 quarter, 3 dimes, and 1 penny.

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3 years ago

Read 2 more answers

If f(x)=x^5-1 g(x)=5x^2 and h(x)=2x which expression is equivalent to [g*f*h](9)

vagabundo [1.1K]

F(x) = x^5 - 1; g(x) = 5x^2; h(x) = 2x

Answer:
$\underbrace{5(\underbrace{(\underbrace{2\cdot9}_{h(9)})^5-1}_{f(g(9))})^2}_{g(f(h(9)))}$ $\boxed{C.}$

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3 years ago

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koban [17]

Answer:

the last one :)

Step-by-step explanation:

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2 years ago