Mitochondrial DNA (mtdna) recovered from a fossil hominin from sima de los huesos in northern spain shows connections to the mtdna of the Denisovans.
The Sima de los Huesos showed distinctive proof of DNA survival over an extended period of time. Based on the enzymatic amplification of a few short mitochondrial DNA (mtDNA) fragments from Middle Pleistocene cave bear bones. Given that the Sima de los Huesos fossils have Neanderthal-derived characteristics (such as in their dental, mandibular, midfacial, supraorbital, and occipital morphology), it is unexpected that the mtDNA from these fossils has a common origin with Denisovan rather than Neanderthal mtDNAs.
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Answer:Dogs have many charateristics and it depends on what dog you own
Explanation:
Answer;
-The conservation of "junk DNA" sequences in diverse genomes suggests that they have important functions.
Explanation;
-The term junk DNA refers to regions of DNA that are noncoding. DNA contains instructions (coding) that are used to create proteins in the cell. However, the amount of DNA contained inside each cell is vast and not all of the genetic sequences present within a DNA molecule actually code for a protein.
-Some of this noncoding DNA is used to produce non-coding RNA components such as transfer RNA, regulatory RNA and ribosomal RNA. However, other DNA regions are not transcribed into proteins, nor are they used to produce RNA molecules and their function is unknown.
Answer:
Multicellular organism is the example of complexity of the natural world.
Explanation:
Multicellular organism such as human which is made of billions of cell. Each cell perform a specific function. The function of one organ is different from the other organ. For example, brain of human is made of millions of neurons which takes instructions from brain to the organs and bring messages from organs to the nervous system in the form of electrical impulses. In short every system in our body is full of complexity.
Answer: The percentage would be 19%, 51% and 30%.
Explanation:
Since we have given that
Number of food eaten by X = 57
Number of food eaten by Y = 153
Number of food eaten by Z = 90
Total number of food eaten = 
So, Food percentage of flock X = 
Food percentage of flock Y = 
Food percentage of flock Z = 
Hence, the percentage would be 19%, 51% and 30%.
