1a) A = 4πpw
/4πw = /4πw
A / 4πw = p
1b) A = 4πpw
22 = 4πp(2)
p = 11/4π (≈0.87)
2a) P = 2πr + 2x
P - 2x = 2πr
/2π /2π
P-2x / 2π = r
2b) P = 2πr + 2x
440 = 2πr + 2(110)
r = 110/π (≈35.014)
Answer:
A) Yes; Week 10 is an outlier since it is the greatest data point.
Answer:
C. x 0 1 2 p(x) 0.35 0.60 0.05
Step-by-step explanation:
50% chance of survival
Let:
x = older eaglet survive
y = younger eaglet survive
Hence,
P(x = 0) (none of the eaglet survive)
P(x = 1) (only one survive)
P(x = 2) (both survive)
P(x) = 0.5
P(x') = 1 - 0.5 = 0.5
P(x n y) = 0.5 * 0.1 = 0.05 ( both survive)
P(only one survive)
P(y n x') + p(y' n x)
(0.5 * 0.3) + (0.5 * (1 - 0.1))
0.15 + 0.45 = 0.6
P(none survives)
1 - (0.60 + 0.05)
= 0.35
X _______ 0 ______ 1 ______ 2
P(x) ____ 0.35 ____ 0.60 ___ 0.05
Answer:true!!!
Step-by-step explanation:
N(3)-8=16
add 8 to both sides
3n=24
Divide each side by three
n=8
