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Oksana_A [137]
3 years ago
14

In the computing industry the average age of professional employees tends to be younger than in many other business professions.

Suppose the average age of a professional employed by a particular computer firm is 28 with a standard deviation of 6 years. A histogram of professional employee ages with this firm reveals that the data are not normally distributed but rather are amassed in the 20s and that few workers are over 40. Apply Chebyshev’s theorem to determine within what range of ages at least 80% of the workers’ ages would fall.
Mathematics
1 answer:
Irina18 [472]3 years ago
8 0
I don’t know but take a piton here and wait and someone with help in 1 Minute
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If f(x) and g(x) are quadratic functions but (f + g)(x) produces the graph below, which statement must be true?
aksik [14]

Answer:

The leading coefficients of f(x) and g(x) are opposites.

4 0
3 years ago
The owner of a convenience store keeps track of how many customer buy lunch food during the "noon rush" each day for four days a
alexdok [17]

Answer:

c) 62.

Step-by-step explanation:

Let x represent number of customers came in on the fifth day.

We have been given that the mean number of customers for those four days is 52. So total number of customers on 4 days would be 4 times 52 that is 208 customers.

We know that mean of a data set is equal to sum of all data points divided by number of data points.

Total number of customers on 5 days would be 208+x and total number of days is 5.

Since we need a mean of 54, so we can set mean of 5 days equal to 54 as:

\frac{208+x}{5}=54

Multiply both sides by 5:

\frac{208+x}{5}*5=54*5

208+x=270

208-208+x=270-208

x=62

Therefore, 62 customers must come in on the fifth day to make the five-day mean 54 and option 'c' is the correct choice.

4 0
3 years ago
Suppose that five ones and four zeros are arranged around a circle. Between any two equal bits you insert a 0 and between any tw
PolarNik [594]

Answer:

Using <u>backward reasoning</u> we want to show that <em>"We can never get nine 0's"</em>.

Step-by-step explanation:

Basically in order to create nine 0's, the previous step had to have all 0's or all 1's. There is no other way possible, because between any two equal bits you insert a 0.

If we consider two cases for the second-to-last step:

<u>There were 9 </u><u>0's</u><u>:</u>

We obtain nine 0's if all bits in the previous step were the same, thus all bit were 0's or all bits were 1's. If the previous step contained all 0's, then we have the same case as the current iteration step. Since initially the circle did not contain only 0's, the circle had to contain something else than only 0's at some point and thus there exists a point where the circle contained only 1's.

<u>There were 9 </u><u>1's</u><u>:</u>

A circle contains only 1's, if every pair of the consecutive nine digits is different. However this is impossible, because there are five 1's and four 0's (we have an odd number of bits!), thus if the 1's and 0's alternate, then we obtain that 1's that will be next to each other (which would result in a 1 in the next step). Thus, we obtained a contradiction and thus assumption that the circle contains nine 0's after iteratins the procedure is false. This then means that you can never get nine 0's.

To summarize, in order to create nine 0's, the previous step had to have all 0's or al 1's. As we didn't start the arrange with all 0's, the only way is having all 1's, but having all 1's will not be possible in our case since we have an odd number of bits.

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5 0
4 years ago
430 randomly selected light bulbs were tested in a laboratory, 224 lasted more than 500 hours. Find a point estimate of the prop
Ray Of Light [21]
The estimated portion of light bulbs that last more than 500 hours will be
x=∑xn=224/430=0.521=52.1%
6 0
3 years ago
If x - 7 = 10, then x = 17. This statement demonstrates:
harkovskaia [24]
C. the addition property of equality
8 0
3 years ago
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