Usual limit of sin is sinX/X--->1, when X--->0
sin3x/5x^3-4x=0/0?, sin3x/3x--->1 when x --->0, so sin3x/5x^3-4x= [3x. sin3x / 3x] /(5x^3-4x)=(sin3x / 3x) . (3x/5x^3-4x)
=(sin3x / 3x) . (3/5x^2- 4)
finally lim sin3x/5x^3-4x=lim (sin3x / 3x) .(3/5x^2- 4)=1x(3/-4)= - 3/4
x----->0 x---->0
Answer:
actually it's 234
brainliest this was hard
Step-by-step explanation:
Answer:
I think it's prove the midpoints are the same
Step-by-step explanation:
I'm not completely sure but I'm taking it right now and I believe that's the most logical answer because if they meet up at the same midpoint then they could bisect each other.
Answer:
6551
Step-by-step explanation:
x=4
9 (4) - 10
9x9x9x9= 6561
6561-10= 6551
