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3 years ago

How are you guys doing today and i need help big time:

Mathematics

1 answer:

Solnce55 [7]3 years ago

4 0

Answer:

Step-by-step explanation:

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Natali5045456 [20]

Answer:

i think Muhammad

Step-by-step explanation:

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3 years ago

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Evaluate the following polynomial. (32mn2 + 50m2n) - (10mn2 - 16m2n + 64).

zaharov [31]

I think the answer is 22mn2+66m2n-64 since there are no more like terms

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4 years ago

Please help me and please do what it says to do

zvonat [6]

Answer:

Step-by-step explanation:

Reduseduse the number with the greatest common factor 4

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4 years ago

Find all solutions in the interval from [0,2pi)<br> 2cos(3x)= -sqrt{2}

algol [13]

Solutions of $2cos(3x)= -\sqrt{2}$ in the interval from [0,2pi) is $x =\frac{\pi}{12}$ and $x = \frac{23\pi}{12}$ .

<u>Step-by-step explanation:</u>

Find all solutions in the interval from [0,2pi)

$2cos(3x)= -\sqrt{2}$

⇒ $2cos(3x)= -\sqrt{2}$

⇒ $\frac{2cos(3x)}{2}= \frac{-\sqrt{2}}{2}$

⇒ $cos3x= \frac{-\sqrt{2}(\sqrt{2})}{2{\sqrt{2}}}$

⇒ $cos3x= \frac{-2}{2{\sqrt{2}}}$

⇒ $cos3x= \frac{-1}{{\sqrt{2}}}$

⇒ $cos^{-1}(cos3x)= cos^{-1}(\frac{-1}{{\sqrt{2}}})$

⇒ $3x=\pm \frac{\pi}{4}$

⇒ $x=\pm \frac{\pi}{12}$

Cosine General solution is :

$x = \pm cos^{-1}(y)+ 2k\pi$

⇒ $x = \pm \frac{\pi}{12}+ 2k\pi$ , k is any integer .

At k=0,

⇒ $x =\frac{\pi}{12}$ ,

At k=1,

⇒ $x = - \frac{\pi}{12}+ 2\pi$

⇒ $x = \frac{23\pi}{12}$

Therefore , Solutions of $2cos(3x)= -\sqrt{2}$ in the interval from [0,2pi) is $x =\frac{\pi}{12}$ and $x = \frac{23\pi}{12}$ .

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3 years ago

K I need help again the last part says triangles

dmitriy555 [2]

Answer:

Step-by-step explanation:

One side is 3, another is 6, and the last side is 9.

8 0

3 years ago

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