The expression of integral as a limit of Riemann sums of given integral is 4 ∑ from i=1 to i=n.
Given an integral .
We are required to express the integral as a limit of Riemann sums.
An integral basically assigns numbers to functions in a way that describes displacement, area, volume, and other concepts that arise by combining infinite data.
A Riemann sum is basically a certain kind of approximation of an integral by a finite sum.
Using Riemann sums, we have :
=∑f(a+iΔx)Δx ,here Δx=(b-a)/n
=f(x)=
⇒Δx=(5-1)/n=4/n
f(a+iΔx)=f(1+4i/n)
f(1+4i/n)=
∑f(a+iΔx)Δx=
∑
=4∑
Hence the expression of integral as a limit of Riemann sums of given integral is 4 ∑ from i=1 to i=n.
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Im confused what do you mena
The common difference in an arithmetic sequence refers to the number that represents the difference between two terms in the sequence.
When you look to the sequence you can see that from a term to other one the numbers are increasing, meaning that the common difference needs to be positive. To find the value of the common difference in an arithmetic sequence you have to select two terms. On this case 2.5 and 6, and 16.5 and 20.
Common Difference= 6-2.5
Common Difference= 3.5
Common Difference= 20-16.5
Common Difference= 3.5
After some calculations, you can conclude that the number representing the common difference in this arithmetic sequence is 3.5.
Answer:
the probability would be a 1/3 or a 1/6 chance i think