Find the product 6.43×0.07

Evaluate the line integral, where C is the given curve. (x + 4y) dx + x2 dy, C C consists of line segments from (0, 0) to (4, 1)

zubka84 [21]

Parameterize the line segments (call them $C_1$ and $C_2$ , respectively, by

$\vec r_1(t)=(1-t)(0,0)+t(4,1)=(4t,t)$

$\vec r_2(t)=(1-t)(4,1)+t(5,0)=(4+t,1-t)$

both with $0\le t\le1$ . Then

$\displaystyle\int_C(x+4y)\,\mathrm dx+x^2\,\mathrm dy$

$=\displaystyle\int_0^1\bigg((4t+4t)(4)+(4t)^2(1)\bigg)\,\mathrm dt+\int_0^1\bigg((4+t+4(1-t))(1)+(4+t)^2(-1)\bigg)\,\mathrm dt$

$=\displaystyle\int_0^115t^2+21t-8\,\mathrm dt=\boxed{\frac{15}2}$

6 0

3 years ago

Helllllp >_< Compare: 1.2057 O 1.1421

vladimir2022 [97]

Answer:

Widal Kit Salmonella Ha, Hb, Hc, Hd, OA, OB, OC, OD

Rapid Labs Widal antigen set contains ready to use concentrated smooth antigen suspensions of the bacilli; S. typhi ‘O’. S. typhi ‘H’. S, paratyphi ‘AO’. S. paratyphi ’BO‘. S. paratyphi ’AH’, S. paratyphi ‘BH’. S. paratyphi ‘CH’. S. paratyphi ‘CO’ and/or polyspecific positive control reactive with these antigens.

When the Widal antigen suspensions are mixed and incubated with the patient’s serum, anti salmonella antibodies present in the patient serum react with the antigen suspensions to give agglutination. Agglutination is a positive test result, indicating presence of anti-salmonella antibodies in the patient serum. No agglutination is a negative test result indicating absence of anti-salmonella antibodies.

Pack size – 8 x 5ml

This kit does NOT contain positive and negative controls

Widal Kit Salmonella Ha, Hb, Hc, Hd, OA, OB, OC, OD

Rapid Labs Widal antigen set contains ready to use concentrated smooth antigen suspensions of the bacilli; S. typhi ‘O’. S. typhi ‘H’. S, paratyphi ‘AO’. S. paratyphi ’BO‘. S. paratyphi ’AH’, S. paratyphi ‘BH’. S. paratyphi ‘CH’. S. paratyphi ‘CO’ and/or polyspecific positive control reactive with these antigens.

When the Widal antigen suspensions are mixed and incubated with the patient’s serum, anti salmonella antibodies present in the patient serum react with the antigen suspensions to give agglutination. Agglutination is a positive test result, indicating presence of anti-salmonella antibodies in the patient serum. No agglutination is a negative test result indicating absence of anti-salmonella antibodies.

Pack size – 8 x 5ml

This kit does NOT contain positive and negative control

Step-by-step explanation:

6 0

3 years ago

Find the sample size required to achieve the given margin of error with SD = 51.02 and z - score = 1.96. Round your answer to th

coldgirl [10]

Answer:

The sample size required is 2500.

Step-by-step explanation:

z-score:

In function of the margin of error M, the z-score is given by: