Direct variation is represented by the equation y = k × x and inverse variation is represented by y = k/x
Table 1:
y = k × x
30 = k × 5
30 = 5k
k = 30/5
k = 6
So,
<em>y = 30 </em>
<em>y = 30 k = 6</em>
<em>y = 30 k = 6x = 5</em>
<em>y = 30 k = 6x = 5Equation: y = 6x</em>
y = k × x
y = 10 × 8
y = 80
So,
<em>y = 80 </em>
<em>y = 80 k = 10</em>
<em>y = 80 k = 10x = 8</em>
<em>y = 80 k = 10x = 8Equation: y = 10x</em>
y = 3x
18 = 3x
x = 18/3
x = 6
So,
<em>y = 18</em>
<em>y = 18k = 3</em>
<em>y = 18k = 3x = 6</em>
<em>y = 18k = 3x = 6Equation: y = 3x</em>
y = 2x²
72 = 2x²
x² = 72/2
x² = 36
x = √36
x = 6
So,
<em>y = 72</em>
<em>y = 72k = 2</em>
<em>y = 72k = 2x = 6</em>
<em>y = 72k = 2x = 6Equation: y = 2x²</em>
Table 2:
y = k/x
5 = k/6
5 × 6 = k
30 = k
So,
<em>y = 5</em>
<em>y = 5k = 30</em>
<em>y = 5k = 30x = 6</em>
<em>y = 5k = 30x = 6Equation: y = 30/x</em>
y = k/x
y = 36/4
y = 9
So,
<em>y = 9</em>
<em>y = 9k = 36</em>
<em>y = 9k = 36x = 4</em>
<em>y = 9k = 36x = 4Equation: y = 36/x</em>
y = 60/x
20 = 60/x
20x = 60
x = 60/20
x = 3
So,
<em>y = 20</em>
<em>y = 20k = 60</em>
<em>y = 20k = 60x = 3</em>
<em>y = 20k = 60x = 3Equation: y = 60/x</em>
y = 24/x
y = 24/12
y = 2
So,
<em>y = 2</em>
<em>y = 2k = 24</em>
<em>y = 2k = 24x = 12</em>
<em>y = 2k = 24x = 12Equation: y = 24/x</em>
Read more:
brainly.com/question/472621
If it’s a factor then it’s 2 but if your doing a expression then it is just 2x+2
<span>-3(-w - u) - (-5 + w)
=-3(-w-u)+-1(-5+w)
=-3(-w-u)+(-1)(-5)+-1w
=-3(-w-u)+5+-w
Distribute
=(-3)(-w)+(-3)(-u)+5+-w
=3w+3u+5+-w
Combine like terms
=3w+3u+5+-w
=(3u)+(3w+-w)+(5)
=3u+2w+5
:)
</span>
Given:
bake sale at least $300
price of each pie is $6.00
let the number of pies be represented by x.
Write the inequality:
6x <u>></u> 300
Solve the inequality:
6x <u>></u> 300
<u>÷6 ÷6</u>
x <u>></u> 50
Graph the inequality.
y = 6x
x is the number of pies sold; x at least 50 and gradually increases.
y is the total sales