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pishuonlain [190]
3 years ago
11

A 4-pint bottle of bleach costs $3.60. What is the price per quart?

Mathematics
1 answer:
Kamila [148]3 years ago
3 0

Answer:

$1.80. 4 pints = 2 quarts. $3.60/2 = $1.80.

Step-by-step explanation:

hope this helps

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I really need help with this. Find the equation of the given line:
kumpel [21]

Answer:

Fill it with number but do it on paper

Step-by-step explanation:

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3 years ago
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Cherie wants to go home in a taxi. She lives 7 miles away. The taxi firm charges $4 plus $1.50 per mile. How much will the fare
Alborosie
You would eventually get 14.5 because 1.50 times 7 is 10.5, plus 4 is 14.5.
5 0
4 years ago
Marcus is 5 19/24 feet tall. Ben is 5 9/16 feet tall. Which of the two boys is taller?
Ksju [112]

well, Marcus and Ben are both 5 feet tall and a little bit more, Marcus is 19/24 more and Ben is 9/16 more, so the 5's in the fraction are the same, so which one is larger, 19/24 or 9/16?

we can simply put both fractions with the same denominator, by <u>multiplying one by the other's denominator</u>, so let's proceed,

\bf \stackrel{\textit{\large Marcus is taller}}{5~feet + \left( \cfrac{19}{24}\cdot \cfrac{16}{16}\implies \boxed{\cfrac{304}{384}} \right)}\qquad \qquad \qquad \stackrel{\textit{\large Ben}}{5~feet + \left( \cfrac{9}{16}\cdot \cfrac{24}{24}\implies \boxed{\cfrac{216}{384}} \right)}

4 0
3 years ago
For vectors u= (3,4) and v= (1,3) find CompuV and the angle between u and v.
vampirchik [111]

Answer:

The angle between the given vectors u and v is \theta=cos^{-1}\left[\frac{3}{\sqrt{10}}\right]

Step-by-step explanation:

Given vectors are \overrightarrow{u}=(3,4) and \overrightarrow{v}=(1,3)

Now compute the dot product of u and v:

\overrightarrow{u}.\overrightarrow{v}=(3,4).(1,3)

  =(3)(1)+(4)(3)

  =3+12

 =15

Now find the magnitude of u and v:

|\overrightarrow{u}|=\sqrt{3^2+4^2}

=\sqrt{9+16}

=\sqrt{25}

=5

|\overrightarrow{u}|=5

|\overrightarrow{v}|=\sqrt{1^2+3^2}

=\sqrt{1+9}

=\sqrt{10}

|\overrightarrow{v}|=\sqrt{10}

To find the angle between the given vectors

\overrightarrow{u}.\overrightarrow{v}=|\overrightarrow{u}|\overrightarrow{v}|cos\theta

\theta=cos^{-1}\left[\frac{\overrightarrow{u}.\overrightarrow{v}}{|\overrightarrow{u}|\overrightarrow{v}|}\right]

=cos^{-1}\left[\frac{15}{5\times \sqrt{10}}\right]

=cos^{-1}\left[\frac{15}{5\times \sqrt{10}}\right]

\theta=cos^{-1}\left[\frac{3}{\sqrt{10}}\right]

Therefore the angle between the vectors u and v is

\theta=cos^{-1}\left[\frac{3}{\sqrt{10}}\right]

3 0
3 years ago
Use the equation below to find c, if a = 43 and b = 49. c=180-a-) ?​
Luden [163]

Answer:

88

Step-by-step explanation:

43 + 49= 92.

Then 180 - 92= 88

C= 88

7 0
3 years ago
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