Answer:
480/(x+60) ≤ 7
Step-by-step explanation:
We can use the relations ...
time = distance/speed
distance = speed×time
speed = distance/time
to write the required inequality any of several ways.
Since the problem is posed in terms of time (7 hours) and an increase in speed (x), we can write the time inequality as ...
480/(60+x) ≤ 7
Multiplying this by the denominator gives us a distance inequality:
7(60+x) ≥ 480 . . . . . . at his desired speed, Neil will go no less than 480 miles in 7 hours
Or, we can write an inequality for the increase in speed directly:
480/7 -60 ≤ x . . . . . . x is at least the difference between the speed of 480 miles in 7 hours and the speed of 60 miles per hour
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Any of the above inequalities will give the desired value of x.
(12 - 2) * 180 = 1,800/12 = 150
(8 - 2) * 180 = 1,080/8 = 135
B. 8 sides
In general, the average rate of change of f (x) on the interval a, b is given by f(b) – f(a) / b – a. The average rate of alteration of a function, f (x) on an interval is well-defined to be the variance of the function values at the endpoints of the interim divided by the difference in the x values at the endpoints of the interval. this is also known as the difference quotient that tells how on average, the y values of a function are changing in connection to variations in the x values. A positive or negative rate of change is applicable which match up to an increase or decrease in the y value among the two data points. It is called zero rate of change when a quantity does not change over time.
<span>x = 5 i beliavie :)..............................</span>
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√(-√2-(-√2))²+(√3-2√3)²= 3
