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2 years ago

112. Which fraction lies between 0.70 and 0.75 on the number line?

2 answers:

7 0

0.71 or 71/100
0.72 or 72/100 (which can be simplified to 18/25)
0.73 or 73/100
0.74 or 74/100 (which can be simplified to 37/50)

Hope my answer helped u :)

lilavasa [31]2 years ago

6 0

Answer:

0.70=70/100

0.75=75/100

Therefore,

Fractions are

71/100,72/100,73/100,74/100

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Answer:

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3 years ago

An alloy of tin is 15% tin and weighs 20 pounds. A second alloy is 10% tin How many pounds of the second alloy

NemiM [27]

Answer:

30 pounds

Step-by-step explanation:

Amount of tin in first alloy + amount of tin in second alloy = amount of tin in mixture

0.15 (20) + 0.10 x = 0.12 (20 + x)

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0.6 = 0.02 x

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2 years ago

Given the following function, find f(-2), f(0), and f(1).<br> f(x) = 5x +5<br><br> f(-2) =

Finger [1]

Answer:

f(-2) = -5

f(0) = 5

f(1) = 10

Step-by-step explanation:

f(-2) = 5(-2) + 5 → -10 + 5 = -5

f(0) = 5(0) + 5 → 0 + 5 = 5

f(1) = 5(1) + 5 → 5 + 5 = 10

4 0

2 years ago

Read 2 more answers

2. When Joey dives off a diving board, the equation of his pathway can be modeled by h = -16- + 15 + 12.

Sergeu [11.5K]

Answer:

a) The maximum height is approx 15.5 unit.

b) The time it will take for Joey to reach the water is 1.45 hour.

Step-by-step explanation:

Given : When Joey dives off a diving board, the equation of his pathway can be modeled by $h(t)= -16t^2+15t + 12$

To find : a) Find Joey's maximum height.

b) Find the time it will take for Joey to reach the water.

Solution :

Modeled $h(t)= -16t^2+15t + 12$ ....(1)

a) To find maximum height

Derivate (1) w.r.t. t,

$h'= -32t+15$

For critical point put h'=0,

$-32t+15=0$

$t=\frac{15}{32}$

$t=0.46875$

Derivate again w.r.t. t,

$h''= -32$

It is maximum at t=0.46875.

Substitute t in equation (1),

$h(0.46875)= -16(0.46875)^2+15(0.46875)+12$

$h(0.46875)= -3.515625+7.03125+12$

$h(0.46875)= 15.515625$

The maximum height is approx 15.5 unit.

b) To find the time it will take for Joey to reach the water.

Put h=0 in equation (1),

$-16t^2+15t + 12=0$

Apply quadratic formula, $x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

Here, a=-16 , b=15, c=12

$t=\frac{-15\pm\sqrt{(15)^2-4(-16)(12)}}{2(-16)}$

$t=\frac{-15\pm\sqrt{225+768}}{-32}$

$t=\frac{-15\pm\sqrt{993}}{-32}$

$t=\frac{-15+\sqrt{993}}{-32},\frac{-15-\sqrt{993}}{-32}$

$t=−0.515,1.453$

Reject negative value.

The time is t=1.45.

The time it will take for Joey to reach the water is 1.45 hour.

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3 years ago

What is the answer to 2.2x-5<-13

Rufina [12.5K]

The answer to this is x<-3.63 repeating

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2 years ago

112. Which fraction lies between 0.70 and 0.75 on the number line? ​

112. Which fraction lies between 0.70 and 0.75 on the number line?