Answer:
132 days to 125.4 days percent of change
Step-by-step explanation:
p= N-O/O x 100% where p is the percent change, is the New value and O is
the Old value. We are given the Old value (132) and the New value (125.4) which we can substitute into the formula to calculate the percent change:
p= 125.4-132/132 x 100%
p= -6.6/132 x 100%
p= (-660/132%)
p= -5%
The type of model that best fits the given situation is; A linear equation Model
<h3>What is the model of the equation?</h3>
Right inside the local reservoir we will have an initial amount of water A.
Now, for every hour that passes by, the amount of water in the reservoir decreases by 500 gals.
Thus, after t hours, the amount of water in the reservoir is expressed as:
W = A - 500gal * t
This is clearly a linear equation model and so we can conclude that the model that fits best in the given situation is a linear model.
The domain of this model is restricted because we can't have a negative amount of water in the reservoir, and as such the maximum value of t accepted is: W = 0 = A - 500gal*t
t = A/500 hours
Therefore, the domain of this linear relation is: t ∈ {0h, A/500 }
Read more about Equation model at; brainly.com/question/25896797
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<u>Options</u>
Answer:
(B)
Step-by-step explanation:
We know that the External Angle = Half the Difference of the Two Arcs
Therefore:
Since FGH is the exterior angle and FEH and FH are the two arcs, then:
Also:
Adding the two equations, we have:
