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Hatshy [7]
3 years ago
8

A store sells a package of 12 trading cards for $5.16. Explain how you can tell that the unit price per card is less than $1. Wh

at is the unit price per card
Mathematics
1 answer:
alexgriva [62]3 years ago
5 0
If the unit price was $1 or more, the price would be $12 or more
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Kai calculates that he spends 15% of the school day in science class. If he spends 42 minutes in science class, how many minutes
MissTica
You need to first multiply 100 by 42 then divide by 15

6 0
3 years ago
What is the slope of the line that connects the points (-1,9) and (3,25)
Snowcat [4.5K]

Answer:

4

Step-by-step explanation:

25-9/3-(-1) =

16/4 = 4

5 0
3 years ago
Read 2 more answers
Given the following functions:
andrew-mc [135]

Answer:

x^2 - 6x + 9.

Step-by-step explanation:

f(x) = x^2 and g(x) = x - 3.

To find f(g(x))  we replace the x in f(x) by g(x).

f(g(x)) = (x - 3)^2

= x^2 - 6x + 9.

5 0
3 years ago
Find the area of the surface. The part of the surface z = xy that lies within the cylinder x2 + y2 = 36.
rewona [7]

Answer:

Step-by-step explanation:

From the given information:

The domain D of integration in polar coordinates can be represented by:

D = {(r,θ)| 0 ≤ r ≤ 6, 0 ≤ θ ≤ 2π) &;

The partial derivates for z = xy can be expressed  as:

y =\dfrac{\partial z}{\partial x} , x = \dfrac{\partial z}{\partial y}

Thus, the area of the surface is as follows:

\iint_D \sqrt{(\dfrac{\partial z}{\partial x})^2+ (\dfrac{\partial z}{\partial y})^2 +1 }\ dA = \iint_D \sqrt{(y)^2+(x)^2+1 } \ dA

= \iint_D \sqrt{x^2 +y^2 +1 } \ dA

= \int^{2 \pi}_{0} \int^{6}_{0} \ r  \sqrt{r^2 +1 } \ dr \ d \theta

=2 \pi \int^{6}_{0} \ r  \sqrt{r^2 +1 } \ dr

= 2 \pi \begin {bmatrix} \dfrac{1}{3}(r^2 +1) ^{^\dfrac{3}{2}} \end {bmatrix}^6_0

= 2 \pi \times \dfrac{1}{3}  \Bigg [ (37)^{3/2} - 1 \Bigg]

= \dfrac{2 \pi}{3} \Bigg [37 \sqrt{37} -1 \Bigg ]

3 0
3 years ago
What is another way to write the absolute value inequality lp|<1 2?
PIT_PIT [208]

Answer:

|p| ≤ 12

Step-by-step explanation:

The absolute value of p less than or equal to 12

8 0
3 years ago
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