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3 years ago

15

In how many days will the inspectors come on the same day

1 answer:

Jet001 [13]3 years ago

8 0

Answer:

depends on situations

Step-by-step explanation:

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Which values from the given replacement set make up the solution set of the inequality? 2b≥6;

Bingel [31]

The answer is A because the variable can’t be no lower than 3 and every other answer has 2 in it. 2•(3) is equal to 6 and 2•(4) is greater than 6 which correlates with the sign (greater than or equal to).

5 0

3 years ago

WHAT WOULD THIS BE!?!!!!!

victus00 [196]

Answer:

B 9

Step-by-step explanation:

Use the rule of exponents for a division. To divide two powers with the same base, write the same base and subtract the exponents.

$\dfrac{a^m}{a^n} = a^{m - n}$

Now do it with your numbers.

$\dfrac{3^4}{3^2} = 3^{4 - 2} = 3^2 = 3 \times 3 = 9$

Answer: B 9

7 0

3 years ago

the coordinates of the vertices of triangle ABC are A (1,-1),B (1,4), and C (8,4). what is the length in units of the line segme

strojnjashka [21]

ab=

$\sqrt{ (x1 - x2} ) ^{2} + ( y1 - y2 ) ^{2}$

$\sqrt{0 - 25}$

5 unit is length

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5 0

3 years ago

Read 2 more answers

Please help me! Its for my big test tomorrow!

Shalnov [3]

QUESTION 11

Given : $\ln(3x-8)=\ln(x+6)$

We take antilogarithm of both sides to get:

$3x-8=x+6$

Group similar terms to get:

$3x-x=6+8$

Simplify both sides to get:

$2x=14$

Divide both sides by 2 to obtain:

$x=7$

12. Given; $\log_3(9x-2)=\log_3(4x+3)$

We take antilogarithm to obtain:

$(9x-2)=(4x+3)$

Group similar terms to get:

$9x-4x=3+2$

$5x=5$

We divide both sides by 5 to get:

$x=1$

13. $\log(4x+1)=\log25$

We take antilogarithm to get:

$(4x+1)=25$

Group similar terms

$4x=25-1$

$4x=24$

Divide both sides by 4

$x=6$

14. Given ; $\log_6(5x+4)=2$

We take antilogarithm to get:

$(5x+4)=6^2$

Simplify:

$(5x+4)=36$

$5x=36-4$

$5x=32$

Divide both sides by 5

$x=\frac{32}{5}$

Or

$x=6\frac{2}{5}$

15. Given: $\log(10x-7)=3$

We rewrite in the exponential form to get:

$(10x-7)=10^3$

$(10x-7)=1000$

$10x=1000+7$

$10x=1007$

Divide both sides by 10

$x=\frac{1007}{10}$

16. Given: $\log_3(4x+2)=\log_3(6x)$

We take antilogarithm to obtain:

$(4x+2)=(6x)$

$2=6x-4x$

Simplify

$2=2x$

Divide both sides by 2

$1=x$

17. Given $\log_2(3x+12)=4$ .

We rewrite in exponential form:

$(3x+12)=2^4$

$(3x+12)=16$

$3x=16-12$

$3x=4$

Divide both sides by 3

$x=\frac{4}{3}$

18. Given $\log_3(3x+7)=\log_3(10x)$

We take antilogarithm to get:

$(3x+7)=(10x)$

Group similar terms:

$7=10x-3x$

$7=7x$

We divide both sides by 7

$x=1$

19. Given: $\log_2x+\log_2(x-3)=2$

Apply the product rule to simplify the left hand side

$\log_2x(x-3)=2$

We take antilogarithm to obtain:

$x(x-3)=2^2$

$x^2-3x=4$

$x^2-3x-4=0$

$(x-4)(x+1)=0$

x=-1 or x=4

But x>0, therefore x=4

20. Given $\ln x+ \ln (x+4)=3$

Apply product rule to the LHS

$\ln x(x+4)=3$

Rewrite in the exponential form to get:

$x(x+4)=e^3$

$x^2+4x=e^3$

$x^2+4x-e^3=0$

This implies that:

$x=-6.91$ or $x=2.91$

7 0

3 years ago

a recipe calls for 1 3/4 cups of flour 1 1/4 cups of white sugar 1/3 cupsmof milk 1/2 cups of walnuts and 1/3 cupmod butter the

Rzqust [24]

Answer:2 1/4 cups of flour for 9 servings Hope its helps ;)

6 0

3 years ago

Read 2 more answers