Meals his menas buy each week. The collected data are below:

Ms. Wilson works at a music store. On Black Friday she sold 6 more than 3 times the number of CDs she sold on Cyber Monday. Ms.

DiKsa [7]

Plz send a picture for me to help you on this thank u

5 0

3 years ago

The table shows the inputs and corresponding outputs for the function f(x) = StartFraction 1 Over 8 EndFraction(2)x. A 2-column

asambeis [7]

Answer:

f-1 (1/2) =2, f-1(8) = 6

Step-by-step explanation:

i did it on edge

5 0

4 years ago

Read 2 more answers

A track star runs two races on a certain day. The probability thathe wins the first race is 0.7, the probability that he wins th

NARA [144]

Answer:

a) 80% probability that he wins at least one race.

b) 30% probability that he wins exactly one race.

c) 20% probability that he wins neither race.

Step-by-step explanation:

We solve this problem building the Venn's diagram of these probabilities.

I am going to say that:

A is the probability that he wins the first race.

B is the probability that he wins the second race.

C is the probability that he does not win any of these races.

We have that:

$A = a + (A \cap B)$

In which a is the probability that he wins the first race but not the second and $A \cap B$ is the probability that he wins both these races.

By the same logic, we have that:

$B = b + (A \cap B)$

The probability that he wins both races is 0.5.

This means that $A \cap B = 0.5$

The probability that he wins the second race is 0.6

This means that $B = 0.6$

$B = b + (A \cap B)$

$0.6 = b + 0.5$

$b = 0.1$

The probability that he wins the first race is 0.7.

This means that $A = 0.6$

$A = a + (A \cap B)$

$0.7 = a + 0.5$

$a = 0.2$

A) he wins at least one race.

This is

$P = a + b + (A \cap B) = 0.2 + 0.1 + 0.5 = 0.8$

There is an 80% probability that he wins at least one race.

B) he wins exactly one race.

This is

$P = a + b = 0.2 + 0.1 = 0.3$

There is a 30% probability that he wins exactly one race.

C) he wins neither race

Either he wins at least one race, or he wins neither. The sum of these probabilities is 100%.

From a), we have that there is an 80% probability that he wins at least one race.

So there is a 100-80 = 20% probability that he wins neither race.

6 0

3 years ago

Find the area of the circle <br><br> r = 6 ft

Andru [333]

If the radius of the circle is 6 feet. Then the area of the circle will be 113.097 square feet.

<h3>What is a circle?</h3>

It is the centre of an equidistant point drawn from the centre. The radius of a circle is the distance between the centre and the circumference.

The radius of the circle is 6 feet.

Then the area of the circle will be

Area = πr²

where r is the radius of the circle. Then we have

Area = π × 6²

Area = 36π

Area = 113.097 square feet

More about the circle link is given below.

brainly.com/question/11833983

#SPJ1

5 0

2 years ago

00:36:46

miskamm [114]

Question:

In some code, letters a, b, c, d and e represent numbers 2, 4, 5, 6 and 10. We just do not know which letter represents which number. Consider the following relationships:

a + c = e,

b – d = d and

e + a = b

Which of the following statements is true?

(A) b = 4, d = 2

(B) a = 4, e = 6

(C) b = 6, e = 2

(D) a = 4, c = 6

Answer:

(B) a = 4, e = 6 is the correct answer.

Explanation:

(A) b = 4, d = 2

a + c = e => a + c = e

b – d = d => 4 - 2 = 2

e + a = b => e + a = 4

We are not able to find out what will be at place of a , c , e by which all other relationships are not getting satisfied. And if we apply numbers by hit and trial they are not getting satisfied.

(B) a = 4, e = 6

a + c = e => 4 + c = 6 => 4 + 2 = 6

b – d = d => b - d = d => 10 - 5 = 5

e + a = b => 6 + 4 = 10

We were able to find all a , b , c , d , e and it satisfies all relationships given.

(C) b = 6, e = 2

a + c = e => a + c = 2

b – d = d => 6 - d = d

e + a = b => e + a = 6

We are not able to find out what will be at place of a , c , d by which all other relationships are not getting satisfied. And if we apply numbers by hit and trial they are not getting satisfied.

(D) a = 4, c = 6

a + c = e => 4 + 6 = 10

b – d = d => b - d = d

e + a = b => e + 4 = b => 10 + 4 = 14(this is not from the numbers as given in question so b can't be equal to 14)

We got stuck at the value of b which was 14 and not given in question so, we can leave this option in between as it is not satisfying the relationships.

Therefore, (B) a = 4, e = 6 is the correct answer.

4 0

3 years ago