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3 years ago

(c) What isthe rate of change for each function? Show your work. (d) Which function has the greater rate of change?

Mathematics

2 answers:

levacccp [35]3 years ago

8 0

Answer:

Linear functions feature a constant rate of change. This is called the slope. The slope can be seen in the table, the equation, and the graph for a line.

Step-by-step explanation:

Scrat [10]3 years ago

8 0

Function 1 (the table) has a slope of -2.

This can be calculated using the slope formula, $m = \dfrac{y_2-y_1}{x_2-x_1}$ . Using (-1,3) and (-2,5):

$m = \dfrac{5-3}{-2-(-1)} = \dfrac{2}{-1} = -2$

Function 2 (the graph) has a slope of about 3.5.

It's hard to know for sure with the blurry picture. If you go from (-1,0) to the y-intercept at about (0,3.5), that gives you a rise of 3.5 and a run of 1, so a slope of 3.5.

3.5 is a greater rate of change than -2.

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Use implicit differentiation to find an equation of the tangent line to the curve at the given point. x2⁄3 + y2⁄3 = 4, −3 3 , 1

STatiana [176]

The complete question is

Use implicit differentiation to find an equation of the tangent line to the curve at the given point. $x^\frac{2}{3} + y^\frac{2}{3} = 4$ , $( -3\sqrt{3} ,1)$

Answer:

Equation of tangent is y = $\frac{1}{\sqrt{3} }$ x + 4

Step-by-step explanation:

We are given the equation

$x^\frac{2}{3} + y^\frac{2}{3} = 4$ ,

upon differentiating

d( $x^\frac{2}{3} + y^\frac{2}{3} = 4$ ) /dx = d(4)/dx

$\frac{2}{3}x^-\frac{1}{3 } + \frac{2}{3}y^ -\frac{1}{3} dy/dx = 0$

dy/dx = $-x^\frac{1}{3} /y^-\frac{1}{3}$ = $-y^\frac{1 }{3}/ x^\frac{1}{3}$

upon substituting the values (x, y)= $( -3\sqrt{3} ,1)$

dy/dx = $\frac{1}{\sqrt{3} }$

equation of the tangent

y - 1 = $\frac{1}{\sqrt{3} }$ ( x- (- $3\sqrt{3}$ ))

y = $\frac{1}{\sqrt{3} }$ x + 4

5 0

3 years ago

Find the required annual interest rate to the nearest tenth of a percent for $1,400 to grow to $1,800 if interest is compounded

Volgvan

Step-by-step explanation:

For this problem, you should use the equation $A=P(1+\frac{r}{n} )^n^t$ . For this problem, A=1800, P=1400, n=4, r=x, t=9.

A = Final Amount

P = Principal (Original Amount)

n = Number of times it is compounded in a year. (Quarterly = 4)

r = Interest Rate (In the equation, you must convert your final answer to percent form)

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4 years ago

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NEED HELP FAST!!!! will mark u as brainliest

Shalnov [3]

Obviously, it's not rational, because it's the sum of two square roots, so cancel out A and B right away.

If we solve it

sqrt (18) + sqrt (2)
= sqrt (9*2) + sqrt (2)
= 3 sqrt (2) + sqrt (2)
= 4 sqrt (2)

D :D

6 0

3 years ago

Halp please, no links or i'll report

loris [4]

The answer is b
I always get links even if we wrote no links this is so annoying they only want points

7 0

3 years ago

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In baseball, the pitcher's mound is 60.5 feet from home plate. If the fastest pitch ever recorded in Major League Baseball was 1

Levart [38]

Answer:

t=0.4 sec

Step-by-step explanation:

Remember that

1 mile=5,280 feet

1 hour=3,600 seconds

Let

s -----> the speed in ft/sec

d ----> the distance in ft

t -----> the time in sec

s=d/t

Solve for t

t=d/s

step 1

Convert miles/hour to ft/sec

105.1 mi/h=105.1(5,280/3,600)=154.15 ft/sec

step 2

Find the time

t=d/s

we have

s=154.15 ft/sec

d=60.5 ft

substitute

t=60.5/154.15

t=0.4 sec

4 0

4 years ago

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(c) What isthe rate of change for each function? Show your work. (d) Which function has the greater rate of change?​

(c) What isthe rate of change for each function? Show your work. (d) Which function has the greater rate of change?