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Tasya [4]
3 years ago
12

Graph the two linear equations y=-2, x=5

Mathematics
1 answer:
Natalka [10]3 years ago
5 0

Answer:

(hope this helps can I pls have brainlist (crown)☺️)

Step-by-step explanation:

In pic

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Help someoneee!!!! <br> ill give a brainliest
Serjik [45]

Answer:

-13.5

Step-by-step explanation:

-4/3w=18

You would need to get the w by itself on one side so the easiest way to do so would be to divide both sides my -4/3.

This would give you an answer of w= -27/2 or w= -13.5

8 0
3 years ago
What is y+2= (-3) (x-4)
TEA [102]
Y=-3x+10 is your awnser
3 0
3 years ago
Read 2 more answers
4(5x-3)=48<br><img src="https://tex.z-dn.net/?f=4%285x%20-%203%29%3D%2048" id="TexFormula1" title="4(5x - 3)= 48" alt="4(5x - 3)
krek1111 [17]
Hello, My Dear Friend!

Solution for 4(5x-3)=48 equation:

<span>Simplifying:
</span>4(5x + -3) = 48<span>

</span><span>Reorder the terms:
</span>4(-3 + 5x) = 48
(-3 * 4 + 5x * 4) = 48
(-12 + 20x) = 48<span>

</span><span>Solving:
</span>-12 + 20x = 48<span>

</span><span>Solving for variable 'x'.
</span>Move all terms containing x to the left, all other terms to the right.
<span>Add '12' to each side of the equation.
</span>-12 + 12 + 20x = 48 + 12<span>

</span>Combine like terms: -12 + 12 = 00 + 20x = 48 + 12
20x = 48 + 12<span>

</span><span>Combine like terms: </span>48 + 12 = 60
20x = 60<span>

</span><span>Divide each side by '20'.
</span>x = 3<span>

</span><span>Simplifying:
</span>x = 3<span>

Therefore, THAT is The Answer!^^^ 

</span>=====> x = 3 <=====

I Hope my answer has come to your Help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead! :)

(Ps. Mark As Brainliest IF Helped!)

-UniteTheSeven, UniteTheLeague, Justice League!!! :D

<span>-TheOneAboveAll :)</span>
5 0
4 years ago
Driving under the influence of alcohol (DUI) is a serious offense. The following data give the ages of a random sample of 50 dri
o-na [289]

Answer:

Explanation below.

Step-by-step explanation:

For this case we have the following dataset:

46, 16, 41, 26, 22 ,33, 30, 22 ,36, 34,

63, 21, 26, 18, 27, 24, 31, 38, 26, 55,

31,  47, 27, 43 ,35, 22 ,64,40, 58, 20,

49, 37, 53, 25, 29, 32, 23, 49, 39, 40,

24, 56, 30, 51, 21, 45, 27, 34, 47, 35

So we have 50 values. The first step on this case would be order the dataset on increasing way and we got:

16, 18, 20, 21, 21, 22, 22, 22, 23, 24,

24, 25, 26, 26, 26, 27, 27, 27, 29, 30

30, 31, 31, 32, 33, 34, 34, 35, 35, 36,

37, 38, 39, 40, 40, 41, 43, 45, 46, 47,

47, 49, 49, 51, 53, 55, 56, 58, 63, 64

We can find the range for this dataset like this:

Range = Max-Min = 64-16 =48

Then since we need 7 classes we can find the length for each class doing this:

W = \frac{48}{7}=6.86

And now we can define the classes like this and counting how many observations lies on each interval we got the frequency:

  Class           Frequency      Midpoint           RF                   CF

________________________________________________

[16-22.86)              8               19.43         (8/50)=0.16           0.16

[22.86-29.71)         11              26.29        (11/50)=0.22          0.38

[29.71-36.57)         11               33.14         (11/50)=0.22          0.6

[36.57-43.43)         7               40.0          (7/50)=0.14           0.74

[43.43-50.29)        6               46.86        (6/50)=0.12          0.86

[50.29-57.14)         4               53.72        (4/50)=0.08         0.94

[57.14-64]               3               60.57        (3/50)=0.06           1.0

________________________________________________

Total                         50                                         1.00

RF= Relative frequency. CF= Cumulative frequency

The relative frequency was calculated as the individual frequency for a class divided by the total of observations (50)

The mid point is the average between the limits of the class.

And the cumulative frequency is calculated adding the relative frequencies for each class.

8 0
4 years ago
A bicyclist is finishing his repair of a flat tire when a friend rides by with a constant speed of 3.63 m/s. Four seconds later,
castortr0y [4]

From the moment the friend passes the bicyclist, his friend covers a distance over time t of (3.63 m/s)*t.

The bicyclist covers a distance of 1/2*(2.11 m/s^2)*t^2. They meet when these distances are equal:

3.63 t = 1.055 t^2  ==>  1.055 t^2 - 3.63 t = 0

==>  t = 0 s   or   t = 3.44 s

5 0
3 years ago
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