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DaniilM [7]
3 years ago
15

Use this parallelogram to answer the question. 12.5 in. 10 in. 26 in. 16.5 in.

Mathematics
1 answer:
Reil [10]3 years ago
4 0

Answer:

The answer is 3

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g What is the probability of being dealt exactly three of a kind (like three kings or three 7’s, etc.) in a five card hand from
Elena L [17]

Answer: 0.02257

Step-by-step explanation:

Given : Total cards in a deck = 52

Number of ways to select any 5 cards : ^{52}C_5

Since , there are total 13 kinds of card (includes Numbers from 2 to 9 and Ace , king, queen and jack).

Of each kind , there are 4 cards.

Number of ways to select three cards in a five card hand of a single kind : ^{4}C_3\times^{48}C_2

Number of ways to select three cards in a five card hand of a exactly three of a kind : 13\times^{4}C_3\times^{48}C_2

Now , the required probability = \dfrac{13\times^{4}C_3\times^{48}C_2}{^{52}C_5}

=\dfrac{13\times4\times\dfrac{48!}{2!46!}}{\dfrac{52!}{5!47!}}\\\\\\=\dfrac{58656}{2598960}

=0.022569027611\approx0.02257

∴ The probability of being dealt exactly three of a kind (like three kings or three 7’s, etc.) in a five card hand from a deck of 52 cards= 0.02257

8 0
3 years ago
Mark for review (Will be highlighted on the review page) 1. Solve this equation: 80 = 3y + 2y + 4 + 1.
saul85 [17]
First combine the like terms 3y + 2y to get 5y. Then combine 4 + 1 to get 5. Your equation will now be 80 = 5y + 5. To solve for y, 5 needs to be subtracted from both sides of the equation leaving 75 = 5y. Final step to solving for y, 5 needs to be divided from each side of the equation leaving the final answer of
15 = y.
7 0
3 years ago
Question 1
Marina CMI [18]

Answer:

1. plane parallel- ABC

2. segment parallel- DA

3. segment parallel- DE

4. segmney skew- FC

3 0
3 years ago
A building may fail by excessive settlement of the foundation or by collapse of the superstructure. Over the life of the buildin
patriot [66]

Answer:

0.1536

Step-by-step explanation:

The computation of probability that the building failure will occur over its life is shown below:-

P(building failure) is

P(ES \cup C)\\\\ = P(ES) + P(C) - P(ES\cap C)\\\\ = P(ES) + P(C) - P(ES) P (C | ES)\\\\ = 0.12 + 0.06 - 0.12 \times 0.22

now we will solve the above equation

= 0.18 - 0.0264

After solving the above equation we will get

= 0.1536

Therefore for computing the probability that the building failure will occur over its life we simply applied the above formula.    

3 0
3 years ago
The solutions to (x + 3)^2- 4=0 are x = -1 and x = -5<br><br> True or false
Neko [114]

Answer:

THE ANSWER WOULD BE TRUE MY FRIEND

6 0
3 years ago
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