Find the maximum value of
1 answer:
9514 1404 393
Answer:
34
Step-by-step explanation:
The graph shows the vertex of the feasible region that is farthest from the origin is (2, 4). These are the values of (x, y) that maximize P.
P = 5(2) +6(4) = 10 +24 = 34
The maximum value of P is 34.
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<em>Additional comment</em>
The feasible region is entirely contained within the first quadrant. We have left off the x ≥ 0 and y ≥ 0 constraints to leave the inequalities uncomplicated.
The graph shows the line 34 = 5x +6y so you can see that it only intersects the feasible region (doubly-shaded area) at the vertex where the objective function is maximized.
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Answer: cos(Θ) = (√15) / 4
Explanation:
The question states:
1) sin(Θ) = 1/4
2) 0 < Θ < π / 2
3) find cos(Θ)
This is how you solve it.
1) Use the fundamental identity (in this part I use α instead of Θ, just for facility of wirting the symbols, but they mean the same for the case).
2) From which you can find:
3) Replace sin(α) with 1/4
=>
=>
4) Given that the angle is in the first quadrant, you know that cosine is positive and the final answer is:
cos(Θ) =
.
And that is the answer.
Explanation:
The question states:
1) sin(Θ) = 1/4
2) 0 < Θ < π / 2
3) find cos(Θ)
This is how you solve it.
1) Use the fundamental identity (in this part I use α instead of Θ, just for facility of wirting the symbols, but they mean the same for the case).
2) From which you can find:
3) Replace sin(α) with 1/4
=>
=>
4) Given that the angle is in the first quadrant, you know that cosine is positive and the final answer is:
cos(Θ) =
And that is the answer.