All categories

3 years ago

:) Alyssa's high school played 18 football games this year. She attended

Mathematics

2 answers:

miss Akunina [59]3 years ago

7 0

Answer:

18-16=2

Step-by-step explanation:

hence she missed to football games

hope this helps!

pls mark me as the brainliest:)

have a great day ahead.!.

Anuta_ua [19.1K]3 years ago

5 0

The answer is 2. Because 18-16=2

You might be interested in

We would like to create a confidence interval.

Vlada [557]

Answer:

c.A 90% confidence level and a sample size of 300 subjects.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level $1-\alpha$ , we have the confidence interval with a margin of error of:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

In this problem

The proportions are the same for all the options, so we are going to write our margins of error as functions of $\sqrt{\pi(1-\pi)}$

a.A 99% confidence level and a sample size of 50 subjects.

$n = 50$

99% confidence interval

So $\alpha = 0.01$ , z is the value of Z that has a pvalue of $1 - \frac{0.01}{2} = 0.995$ , so $Z = 2.575$ .

The margin of error is

$M = z\sqrt{\frac{\pi(1-\pi)}{n}} = \frac{2.575}{\sqrt{50}}\sqrt{\pi(1-\pi)} = 0.3642\sqrt{\pi(1-\pi)}$

b.A 90% confidence level and a sample size of 50 subjects.

$n = 50$

90% confidence interval

So $\alpha = 0.1$ , z is the value of Z that has a pvalue of $1 - \frac{0.1}{2} = 0.95$ , so $Z = 1.645$ .

The margin of error is

$M = z\sqrt{\frac{\pi(1-\pi)}{n}} = \frac{1.645}{\sqrt{50}}\sqrt{\pi(1-\pi)} = 0.2623\sqrt{\pi(1-\pi)}$

c.A 90% confidence level and a sample size of 300 subjects.

$n = 300$

90% confidence interval

So $\alpha = 0.1$ , z is the value of Z that has a pvalue of $1 - \frac{0.1}{2} = 0.95$ , so $Z = 1.645$ .

The margin of error is

$M = z\sqrt{\frac{\pi(1-\pi)}{n}} = \frac{1.645}{\sqrt{300}}\sqrt{\pi(1-\pi)} = 0.0950\sqrt{\pi(1-\pi)}$

This produces smallest margin of error.

d.A 99% confidence level and a sample size of 300 subjects.

$n = 300$

99% confidence interval

So $\alpha = 0.01$ , z is the value of Z that has a pvalue of $1 - \frac{0.01}{2} = 0.995$ , so $Z = 2.575$ .

The margin of error is

$M = z\sqrt{\frac{\pi(1-\pi)}{n}} = \frac{2.575}{\sqrt{300}}\sqrt{\pi(1-\pi)} = 0.1487\sqrt{\pi(1-\pi)}$

6 0

3 years ago

Darnell team scored 40 points at the game Donald score 15% of the teams points how many points the Darnell score

andriy [413]

Donald scores 6 points

3 0

3 years ago

Cuanto le falta a 425,000 para llegar a 500,000<br><br> Ayúdenme por favor

Sauron [17]

Answer:

375,000 no se sisera esa

4 0

3 years ago

Read 2 more answers

Look below at the image provided.

vesna_86 [32]

That would be angle 2. It is on the opposite of angle 7 and it is inside the two parallel lines

Hope this helped!

~Just a girl in love with Shawn Mendes

5 0

3 years ago

I need the answer please

eduard

Answer:

bujvunvyjctn

Step-by-step explanation:

v uh yhfnx zhjd dd djsi dh

Sorry i dont know but if you want points you could spam things like this and get points

8 0

2 years ago