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3 years ago

pls help me with this i’ve been stuck on it for a while but i did it on paper and it doesn’t look right

Mathematics

1 answer:

inn [45]3 years ago

5 0

i will fill the boxes from top down

4(-2)-5=-13

4(1)-5=-1

4(2)-5=3

4(3)-5=7

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Bailey will roll a number cube and flip a coin for a probability experiment. The faces of the number cube are labeled 1 through

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Jill buys a t-shirt for $12.79 and a pair of socks for $6.75 at the mall. How much did she spend?

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Step-by-step explanation:

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2 years ago

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What is the constant of proportionality between y and x in the graph?

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Answer:

y=3x

Step-by-step explanation:

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2 years ago

3. A balancing balloon toy is in the shape of a hemisphere (half-sphere) attached to the base of a cone. If the toy is 4ft tall

Katen [24]

Answer:

The volume of the toy is $V=5.23\ ft^3$

Step-by-step explanation:

step 1

Find the volume of the hemisphere

The volume of the hemisphere is given by the formula

$V=\frac{2}{3}\pi r^{3}$

In this problem, the wide of the toy is equal to the diameter of the hemisphere

$D=2\ ft$

$r=2/2=1\ ft$ ----> the radius is half the diameter

substitute

$V=\frac{2}{3} \pi (1)^{3}=\frac{2}{3} \pi\ ft^3$

step 2

Find the volume of the cone

The volume of the cone is given by

$V=\frac{1}{3}\pi r^{2}h$

we know that

The radius of the cone is the same that the radius of the hemisphere

$r=1\ ft$

The height of the cone is equal to subtract the radius of the hemisphere from the height of the toy

$h=4-1=3\ ft$

substitute the given values

$V=\frac{1}{3}\pi (1)^{2}(3)=\pi\ ft^3$

step 3

Find the volume of the toy

we know that

The volume of the toy, is equal to the volume of the cone plus the volume of the hemisphere.

$V=(\frac{2}{3} \pi+\pi)\ ft^3$

$V=(\frac{5}{3}\pi)\ ft^3$

assume

$\pi=3.14$

$V=\frac{5}{3}(3.14)=5.23\ ft^3$

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Mean: 4
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