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3 years ago

pls help me with this i’ve been stuck on it for a while but i did it on paper and it doesn’t look right

Mathematics

1 answer:

inn [45]3 years ago

5 0

i will fill the boxes from top down

4(-2)-5=-13

4(1)-5=-1

4(2)-5=3

4(3)-5=7

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Which of the following is the equation of a line that passes through the point (1,4) and is parallel to the x-axis?

Alexandra [31]

A because , well Y=4 and the points y coordinate is 4. And when a line is Y= a certain number, its a horizontal line parallel to x axis

8 0

3 years ago

Howdy! Id love to have these questions answered asap! Thank you for the help!

tiny-mole [99]

Answer:

1. B.

2. B.

Step-by-step explanation:

Trigonometry

1) Coterminal angles can be found by adding or subtracting 360° (or 2\pi radians) to a given angle. If we have 120°, adding 360° gives 480°, adding again 360° gives 840°. There is no way to get -180°, so this option is not a coterminal angle to 120°

A. $Cos (-90^o)=0$ , and not undefined

B. $Sin (-90^o)=-1$ . This is correct

C. $Tan (-90^o)$ is undefined, not zero

Thus the only correct option is B.

8 0

3 years ago

Order the number least to greatest 4.32 , 4.5 , 4.312 , 4.316

dmitriy555 [2]

4.312, 4.316, 4.32, 4.5

I hope this helps ^W^ have a great day!

3 0

3 years ago

Read 2 more answers

Solve for y in the proportion

maxonik [38]

Answer:

y = 1

Step-by-step explanation:

$\frac{y + 3}{16} = \frac{2}{8} \\ = > y + 3 = \frac{2 \times 16}{8} \\ = > y + 3 = 2 \times 2 \\ = > y + 3 = 4 \\ = > y = 4 - 3 \\ = > y = 1$

8 0

3 years ago

More than three-quarters of the nation’s colleges and universities now offer online classes, and about 23% of college graduates

RUDIKE [14]

Answer:

0.1997 or 19.97%

Step-by-step explanation:

Have taken course online (H) = 23%

Have NOT taken course online (N) = 77%

Have taken course online and don't believe they provide same value (H&D) = 61%

Have NOT taken course online and don't believe they provide same value (N&D) = 73%

The probability that a student has taken a course online given that she does not believe that online courses provide the same educational value as one taken in person is;

$P(H|D)=\frac{P(H)*P(H\&D)}{P(H)*P(H\&D)+P(N)*P(N\&D)}\\P(H|D)=\frac{0.23*0.61}{0.23*0.61+0.77*0.73}\\P(H|D)=0.1997$

There is a 0.1997 or 19.97% chance that she has taken an online course before.

3 0

4 years ago