The distance of segment AX sis found to be 8.6 units using the distance formula.
<h3>What exactly is the distance formula?</h3>
- is the distance formula. This works for any two points in two-dimensional space with coordinates (x₁, y₁) for the first and (x₂, y₂) for the second.
- You may easily remember it if you remember that it is Pythagoras' theorem, that the distance is the hypothenuse, and that the coordinate lengths are the difference between the x and y components of the points.
<h3>Why do we employ the distance formula?</h3>
- In complex numbers, the distance formula is used to express the plane and its magnitude.
- Furthermore, distance formulae can be used to calculate the distance between two planes in three-dimensional or n-dimensional planes. It is also used to calculate the magnitude formula.
Given: A(-4, 5), X (1, −2)
We need to find the distance of the segment AX.
Distance of AX is given as :
Therefore, the distance of segment AX sis found to be 8.6 units using the distance formula.
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Answer:
third option
Step-by-step explanation:
Using De Moivre's theorem
( + i)³ , then
| + i |
=
= = = 2
arg( + i) = ( ) =
Thus
( + i)³
= 2³ [ cos(3 × ) + isin( 3 × ) ]
= 8 [ cos() + isin( ) ]
A. 30
It is derived from 180