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marusya05 [52]
3 years ago
10

2 4/5 in decimal form

Mathematics
1 answer:
tigry1 [53]3 years ago
4 0

Answer:

2.8

Step-by-step explanation:

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Prove the trigonometric identity
Annette [7]

Answer:

Proved See below

Step-by-step explanation:

Man this one is a world of its own :D Just a quick question are you a fellow Add Math student in O levels i remember this question from back in the day :D Anyhow Lets get started

For this question we need to know the following identities:

1+tan^{2}x=sec^2x\\\\1+cot^2x=cosec^2x\\\\sin^2x+cos^2x=1

Lets solve the bottom most part first:

1-\frac{1}{1-sec^2x} \\\\

Take LCM

1-\frac{1}{1-sec^2x} \\\\\frac{1-sec^2x-1}{1-sec^2x} \\\\\frac{-sec^2x}{1-sec^2x} \\\\\frac{-(1+tan^2x)}{-tan^2x}

now break the LCM

\frac{-1}{-tan^2x}+\frac{-tan^2x}{-tan^2x}\\\\\frac{1}{tan^2x}+1\\\\cot^2x+1

because 1/tan = cot x

and furthermore,

cot^2x+1\\cosec^2x

now we solve the above part and replace the bottom most part that we solved with cosec^2x

\frac{1}{1-\frac{1}{cosec^2x} } \\\\\frac{1}{1-sin^2x} \\\\\frac{1}{cos^2x}\\\\sec^2x

Hence proved! :D

4 0
3 years ago
Plz help i will give brainly!
Irina-Kira [14]

Answer:

The answer is c

Step-by-step explanation:

6 0
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How many solutions does the equation −2y + 2y + 3 = 3 have? One Zero Infinitely many Three
AnnZ [28]

Answer:

Infinitely many solutions.

Step-by-step explanation:

In the equation −2y + 2y + 3 = 3  we see only one variable, and that variable is of the first power.  Ordinarily, we'd say that this equation will have 1 solution.  However, if we combine like terms, we get 0 + 3 = 3, or 0 = 0, which is true for any and all y values.  Infinitely many solutions.

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umka2103 [35]

Answer:the last box

Step-by-step explanation:the other ones wouldnt make any sense

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A biased coin is tossed 40 times. Out of those 40 tosses, the coin landed on heads 12 times.
Ierofanga [76]

Answer:

Step-by-step explanation:The probability of picking the biased coin: P(biased coin)=1/100. The probability of all three tosses is heads: P(three heads)=1×1+99×18100. The probability of three heads given the biased coin is trivial: P(three heads|biased coin)=1.

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