The product of multiplying the ones digit of 59 by 853 is 7677 and the product of multiplying the tens digit of 59 by 853 is 42650 and the final product is 50327
<h3>How to determine the product of the numbers?</h3>
The numbers are given as
853 and 59
By using the standard algorithm i.e. the partial product method, we have the following equation
853 * 59 = 853 * (50 + 9)
Open the bracket
So, we have
853 * 59 = 853 * 50 + 853 * 9
Evaluate the products
So, we have
853 * 59 = 42650 + 7677
The above means that the product of multiplying the ones digit of 59 by 853 is 7677 and the product of multiplying the tens digit of 59 by 853 is 42650
Next, we evaluate the sum
853 * 59 = 50327
This means that the final product is 50327
Read more about products at
brainly.com/question/10873737
#SPJ1
The answer is (7, -26) for The second endpoint.
We'll call the midpoint M. In order to find this, we must first note that to find a midpoint we need to take the average of the endpoints. To do this we add them together and then divide by 2. So, using that, we can write a formula and solve for each part of the k coordinates. We'll start with just x values.
(Ux + Vx)/2 = Mx
(Vx + 3)/2 = 5
Vx + 3 = 10
Vx = 7
And now we do the same thing for y values
(Uy + Vy)/2 = My
(Vy + 6)/2 = -10
Vy + 6 = -20
Vy = -26
This gives us the final point of (7, -26)
I think that the answer is 61 I got this off of google so I'm not 100 percent sure please don't take my word as anything but second advice.
Answer:
The missing leg is 8 feet and the hypotenuse is 10 feet.
Step-by-step explanation:
Use the Pythagorean theorem which is A²+B²=C².
So we know the first side is 6 so plug that into the equation which would now be 6²+B²=C².
Because the hypotenuse is 2 feet longer than the missing leg we can plug in C=B+2 which would now make it 6²+B²=(B+2)².
Now we solve what we have so far which would now make the equation 36+B²=B²+4B+ 4.
Now we can figure out that 4B=32.
Now isolate the variable, B, by divide both side of 4B=32 by 4.
This gives us B=8.
So the other side is 8 feet.
Since we know that the hypotenuse is 2 feet longer than the leg we just add 2 feet to the original 8 feet to find the hypotenuse to be 10 feet.
Rewriting the left hand side,
csc²t - cost sec t
= (1/sin²t)-(cost)(1/cost)
= 1/sin²t - 1
= 1/sin²t - sin²t/sin²t
= (1-sin²t)/sin²t
= cos²t/sin²t
= cot²t
