Hello!
We can write this as the system of equations below. We have boxes A, B, and C.
A+B+C=9
B=A+1
C=B+1
First of all we can plug our B and C values into the first equation and solve for A.
A+A+1+A+1+1=9
3a+3=9
3a=6
a=2
Now we can plug our a value into the other equations.
B=2+1
B=3
C=3+1
C=4
Therefore, there are 2 rocks in one box, three in another, and 4 in the last.
I hope this helps!
Answer:
solution contained in the attached files below
Step-by-step explanation:
Answer:
The discriminant is 0
There is 1 real solution
Step-by-step explanation:
Use the discriminant formula, D = b² - 4ac
In the equation y = x² - 4x + 4, a is 1, b is -4, and c is 4.
Plug in these values into the formula:
D = b² - 4ac
D = (-4)² - 4(1)(4)
D = 16 - 4(4)
D = 16 - 16
D = 0
So, the discriminant is 0.
With a discriminant of zero, there is one real solution.
So, the number of real solutions is 1.
Answer:Marti is not correct as a rhombus is not a kite . there are various difference between a rhombus and a kite . all sides of a rhombus are equal whereas all sides of a kite are not equal
Step-by-step explanation:
