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since it has a diameter of 28, then its radius must be half that or 14.
![\textit{area of a circle}\\\\ A=\pi r^2~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r=14 \end{cases}\implies A=\pi (14)^2\implies A=196\pi ~\hfill \stackrel{\stackrel{semi-circle}{half~that}}{98\pi }](https://tex.z-dn.net/?f=%5Ctextit%7Barea%20of%20a%20circle%7D%5C%5C%5C%5C%20A%3D%5Cpi%20r%5E2~~%20%5Cbegin%7Bcases%7D%20r%3Dradius%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20r%3D14%20%5Cend%7Bcases%7D%5Cimplies%20A%3D%5Cpi%20%2814%29%5E2%5Cimplies%20A%3D196%5Cpi%20~%5Chfill%20%5Cstackrel%7B%5Cstackrel%7Bsemi-circle%7D%7Bhalf~that%7D%7D%7B98%5Cpi%20%7D)
Step-by-step explanation:
4 cup of sugar = 6 cup of flour
4.5 cup of sugar = 6.75 cup of flour
5 cup of sugar = 7.5 cup of flour
7.5 cup of sugar = 11.25 cup of flour
8 cup of sugar = 12cup of flour
hope it helps you
Answer:
12 m
Step-by-step explanation:
The path of a football has been modeled by the equation:

where h represents the height and d represents the horizontal distance.
When the ball lands, it means that its height is back at 0 metres. This means that we have to find horizontal distance, d, when height, h, is 0.
=> 


∴ d = 0 m
and
10d - 120 = 0
=> d = 120 / 10 = 12 m
There are two solutions for d when h = 0 m.
The first solution (d = 0 m) is a case where the ball has not been thrown at all. This means the ball has not moved away from the football player and it is still on the ground.
The second solution is the answer to our problem (d = 12 m). The ball lands at a horizontal distance of 12 m
Answer:
RC = 40
Step-by-step explanation:
Note that the circumcentre is equally distant from the triangle's 3 vertices.
That is : PC = RC = QC
Equate any pair and solve for x
Using RC = PC, then
5x - 15 = 3x + 7 ( subtract 3x from both sides )
2x - 15 = 7 ( add 15 to both sides )
2x = 22 ( divide both sides by 2 )
x = 11
Hence
RC = (5 × 11) - 15 = 55 - 15 = 40 units