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saul85 [17]
3 years ago
15

Goran wants to earn more than $58 trimming trees. He charges $7 per hour and pays $5 in equipment fees. What are the possible nu

mbers of hours Goran could trim trees?
Mathematics
1 answer:
Goryan [66]3 years ago
6 0

9514 1404 393

Answer:

  more than 9 hours

Step-by-step explanation:

Goran's net earnings for h hours work will be ...

  7h -5 . . . . hourly pay less equipment fees

He wants this amount to be more than $58:

  7h --5 > 58

  7h > 63 . . . . . add 5

  h > 9 . . . . . . divide by 7

Goran could trim trees for more than 9 hours.

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Does anyone know the answer?
Alex787 [66]

Answer:

£0.60

Step-by-step explanation:

If each pack costs £1.59 and Nadia orders 15 packs,

then the total order before discount = 1.59 x 15 = £23.85

From the table given, we can see that for an order of £23.85 a 2.5% discount will be applied.

Divide £23.85 by 100 to get 1%:  £23.85 ÷ 100 = £0.2385

Now multiply by 2.5 to get 2.5%:  £0.2385 × 2.5 = £0.59625 = £0.60

Alternatively, the calculation in one expression is:

(1.59 × 15) × 0.025 = 0.59625

7 0
2 years ago
Work out the circumference of this circle.
nevsk [136]

Answer:

About 28.3

Step-by-step explanation:

Formula=2\pir

r=radius

d=diameter

radius is 1/2 of diameter

The diameter is 9 so the radius is 4.5

6 0
3 years ago
Find the logarithmic form of 54 = 625
tankabanditka [31]

Answer:

4 log 5 = log 625.

Step-by-step explanation:

I am assuming you mean 5^4 = 625

Taking logs

log 5^4 = log 625

4 log 5 = log 625.

3 0
3 years ago
Easy points, please help
kicyunya [14]
-18+ 3(5x-2)+8

Distribute
-18+15x-6+8

Combine all like terms
15x-16

Final answer: 15x-16
8 0
4 years ago
Read 2 more answers
A) Write the exponential equation to represent a house purchased for
dsp73

Answer:

= A(t) = 120000(1.06)^t   t = 1 year

We just add ^12 to equal 1/12 months.

Then use the notation below.

Step-by-step explanation:

We simply want to write an equivalent form of the same equation that will allow for the time period to be calculated in years.

For one year, t = 1, we want it to grow 6% = 1.06

Yearly Rate of Growth annual equation: = 7200

P(i) 7200/ 120000 x 100% = 6% per year growth rate

the yearly growth factor is 1 + appreciation rate = 1+i =1+0.06= 1.06

So time in years can be added to t

= A(t) = 120000(1.06)^t   t = 1 year

The yearly growth factor = 1.06

To equate monthly we add the exponent  t*12*1/12 before  120000(1.06)^t

then add 1/12 to replace ^t = monthly, or just keep the t= time

A(t) = 120000(1.06)^12t

4 0
3 years ago
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