Question

A rectangular parking lot has a perimeter of 500 feet. The width is 20 feet less than the length. Find the dimensions of the parking lot.

Answer 1

Answer:

115ft and 135 ft

Step-by-step explanation:

L - length

W - width

If width is x ft, then length is (x+20)

Put all in perimeter formula

500= 2 times ((x+20)+x)

500= 2 times (x+20)+x)

500=2 times (2x+20)

500=4x+40

4x=500-40

4x=460

x=460/4

So width is 115 ft, then length is 115+20=135 ft