Answer:
5.86
Step-by-step explanation: its right on delta math
Volume of a cylinder = π r² h
Let us assume the following values:
radius = 9
height = 10
Volume = 3.14 * 9² * 10
= 3.14 * 81 *10
Volume = 2,543.40
Changes:
radius is reduced to 2/9 of its original size = 9 x 2/9 = 2
height is quadrupled = 10 x 4 = 40
Volume = π r² h
= 3.14 * 2² * 40
= 3.14 * 4 * 40
Volume = 502.40
Original volume = 2543.40 V.S. Volume after change = 502.40
The volume of an oblique cylinder decreased when its radius was decreased to 2/9 of its original size and its height is increased 4 times.
Answer:
(x^2 + x -1) x (x^2+3x-3)
Step-by-step explanation:
-6x-5+x^4+4x^3-x^2+8
-6x+3+x^4+4x^3-x^2
-6x+3+x^4+x^3+3x^3-x^2
-3x-3x+3+x^2 x(x^2+x-1)+3x^3 +3x^2-3x^2
3x *(x^2+x+x-2)-3(x^2+x-1)+x^2 *(x^2+x-1)
= (x^2+x-1) x (x^2+3x-3)
* means multiply btw
Less because 3×3=6 and 6 and 16 arent equal
